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arlik [135]
3 years ago
13

49:05

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0
The correct answer is D
You might be interested in
Compare the decimals 121.3 and 121.30
stich3 [128]
They are the same thing
5 0
4 years ago
Read 2 more answers
What value of x is in the solution set of -2(3x + 2) > -8x + 6?
n200080 [17]

Answer:

x > 5

Step-by-step explanation:

Given that:

= -2(3x + 2) > -8x + 6

 (negative sign before bracket will alter the internal signs when multiplied by each term)

= -6x - 4 > -8x +6

Taking x terms on left side and other constants on right side

= -6x + 8x > 6 +4

Signs will be changer for transferred terms

= 2x > 10

By Dividing both sides 2 we get

=x > 10/2

= x >5

5 0
3 years ago
Solve (1/3)² ÷ (1/3)⁷ = 3ⁿ ​
Zarrin [17]

Answer:

n=5

Step-by-step explanation:

(1/3)^2 divided by (1/3)^7 = 243

3^5=243

8 0
2 years ago
Read 2 more answers
Multiplicar:
oksian1 [2.3K]

Answer:

a. 42

b. -12x-5

c. -60

d. -75

e. 66

f. -90

g. 144

h. -135

4 0
3 years ago
Lim x—&gt; -2 <br> sqrt(3x+10) -2/ x+2
snow_lady [41]

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}

Rationalize the numerator:

\dfrac{\sqrt{3x+10}-2}{x+2}\cdot\dfrac{\sqrt{3x+10}+2}{\sqrt{3x+10}+2}=\dfrac{(3x+10)-4}{(x+2)(\sqrt{3x+10}+2)}=\dfrac3{\sqrt{3x+10}+2}

where the x+2 factors in the numerator and denominator cancel. Then the limit is

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}=\lim_{x\to-2}\frac3{\sqrt{3x+10}+2}=\frac3{\sqrt4+2}=\boxed{\frac34}

8 0
3 years ago
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