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tatyana61 [14]
3 years ago
13

Write a general expression for the force that the spring exerts on the mass, in term of k and x. Choose the initial position of

the front of the spring to be xi

Physics
1 answer:
Harrizon [31]3 years ago
6 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is F_{spring} =  - k  * x_f

Explanation:

Generally  the force exerted on the mass by the spring is mathematically represented as

         F_{spring} =  - k  *  \Delta x

Here the negative sign  shows that the force is acting in the negative x axis

        k is the spring constant

  and  \Delta x is the distance through which the spring moves the mass which is mathematically evaluated as

      \Delta x =  x_f -x_i

=>   F_{spring} =  - k  * [ x_f -x_i]

Given that  x_i  =  0 \  m

   F_{spring} =  - k  * x_f

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What is the gravitational force between Mars and the sun? 7.43 × 1030 N 1.79 × 1026 N 1.65 × 1021 N 3.76 × 1032 N
VMariaS [17]

The gravitational force between Mars and the Sun is 1.65\cdot 10^{21} N

Explanation:

The magnitude of the gravitational force between two objects is given by  the equation:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, we have:

m_1 = 1.99\cdot 10^{30} kg is the mass of the Sun

m_2 = 6.39\cdot 10^{23} kg is the mass of Mars

r=229\cdot 10^6 km = 229\cdot 10^9 m is the average distance Mars-Sun

Substituting into the equation, we find the gravitational force:

F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(6.39\cdot 10^{23})}{(229\cdot 10^9)^2}=1.62\cdot 10^{21} N

So, the closest answer is

1.65\cdot 10^{21} N

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The waste product of photosynthesis is:
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A student has a displacement of 739 m north in 162 s. What was the student’s average velocity?A. 0.22 m/sB. 119,718 m/sC. 162 m/
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Answer:

answer below

Explanation:

Displacement of the student is 739 m due North and it takes 162 s.

We need to find the student's average velocity. Using formula of velocity.

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