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shutvik [7]
3 years ago
11

In an isolated system, bicycle 1 and bicycle 2, each with a mass of 15 kg, collide. bicycle 1 was moving to the right at 1 m/s,

while bicycle 2 was moving to the left at 3 m/s. what is the magnitude of their combined momentum before the crash?
Physics
1 answer:
IgorC [24]3 years ago
6 0
To do this, all you need to do is get the momentum of each and get the sum. The formula of momentum is:

p=mv

where:
p = momentum
m = mass
v = velocity

Bicycle 1 and 2 have the same mass of 15 kg

Bicycle 1 v = 1 m/s
Bicycle 2 v = 3 m/s but because it was coming from the opposite direction then we get a negative velocity. The negative just indicates the direction so it will be -3m/s

m1v1+m2v2

=(15kg)(1m/s) + (15kg)(-3m/s) 
= 15kg.m/s + (-45kg.m/s)
=-30kg.m/s

Their combined momentum before the crash is 30kg.m/s. We take out the negative sign because the question is asking only for the magnitude and not the direction and remember the negative sign indicates the direction. 

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A brass rod is 185 cm long and 1.60 cm in diameter. What force must be applied to each end of the rod to prevent it from contrac
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Answer:

42000N

Explanation:

First you calculate how much it would contract, and secondly you then calculate the force to stretch it by that amount.

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∆L = αL∆T = (19e-6)(1.85)(110) = 0.00387 meter or 3.87 mm

Second part involves linear elasticity.

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F = EA∆L/L

F = (100e9)(0.0002)(0.00387) / (1.85)

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4 0
3 years ago
Can someone please help me think of an idea for this. My teacher wants me to think of a gadget that uses two simple machines, an
ohaa [14]
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8 0
3 years ago
Read 2 more answers
What is the kinetic energy of a toy truck with a mass of 0.75 kg and a velocity of 4 m/s? (Formula: )
Dvinal [7]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is the energy of an object or particle when it is in motion.

Mathematically,   Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

It is given that toy truck has mass = 0.75 kg, and velocity = 4 m/s.

Calculate the kinetic energy as follows.

           Kinetic energy = \frac{1}{2}mass \times (velocity)^{2}

                                    = \frac{1}{2}0.75 kg \times (4 m/s)^{2}

                                     = \frac{1}{2}0.75 kg \times 16 m^{2}/s^{2}

                                     = 0.75 kg \times 8 m^{2}/s^{2}

                                     =  6 kg m^{2}/s^{2}

or,       Kinetic energy = 6 joules

Thus, we can conclude that kinetic energy of toy truck is 6 J.


6 0
4 years ago
Read 2 more answers
A cheetah runs at a constant velocity of 7 m/s. What is it’s acceleration in m/s/s<br> PLEASE HELP
uysha [10]

Answer:

0 m/s²

Explanation:

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5 0
3 years ago
A package of mass 5 kg sits on an airless asteroid of mass 7.6 × 1020 kg and radius 8.0 × 105 m. We want to launch the package i
Effectus [21]

Answer:

s =  1.7 m

Explanation:

from the question we are given the following:

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mass of the asteriod (M) = 7.6 x 10^{20} kg

radius = 8 x 10^5 m

velocity of package (v) = 170 m/s

spring constant (k) = 2.8 N/m

compression (s) = ?

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• Ef = kinetic energy of the object

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• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}  

• s = \sqrt{\frac{m}[k}(v^{2}+\frac{2GM}{r})}

s = \sqrt{\frac{5}[2.8 x 10^5}(170^{2}+\frac{2 x 6.67 x10^{-11} x 7.6 x 10^{20}}{8 x 10^5})}

s =  1.7 m

7 0
3 years ago
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