Answer:
V = 381.70 m³
Explanation:
ρ air = 1.28 kg / m³
ρ helium = 0.18 kg / m³
R = 4.5 m
Vb = 0.068 m³
mb = 123 kg
To determine the volume of helium in the balloon when fully inflated
V = 4 / 3 π * R ³
V = 4 * π / 3 ( 4.5 m )³
V = 381.70 m³
To determine the mass total
m = ρ helium * V
m = 0.18 kg / m³ * 381.70 m³
m = 68.70 kg
mt = ( 68.70 + 123 )kg
mt = 191.70 kg
Answer:
" In the Balmer series, the transitions happening in visible range are considered, which range from around 400 nm to 700 nm. The longest wavelength visible in the Balmer series is 656 nm."
Explanation:
Hope this is helpful :)
It will increase..........................
In order to answer these questions, we need to know the charges on
the electron and proton, and then we need to know the electron's mass.
I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were.
Ok, Rameses:
Elementary charge . . . . . 1.6 x 10⁻¹⁹ coulomb
negative on the electron
plussitive on the proton
Electron rest-mass . . . . . 9.11 x 10⁻³¹ kg
a). The force between two charges is
F = (9 x 10⁹) Q₁ Q₂ / R²
= (9 x 10⁹ m/farad) (-1.6 x 10⁻¹⁹C) (1.6 x 10⁻¹⁹C) / (5.35 x 10⁻¹¹m)²
= ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²
= 8.05 x 10⁻⁸ Newton .
b). Centripetal acceleration =
v² / r .
A = (2.03 x 10⁶)² / (5.35 x 10⁻¹¹)
= 7.7 x 10²² m/s² .
That's an enormous acceleration ... about 7.85 x 10²¹ G's !
More than enough to cause the poor electron to lose its lunch.
It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use " F = MA "
either.
I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
whether F = M A .
I'm going to leave that step for you. Good luck !
<u>Halfway</u><u> between the like poles of two magnets, because the field lines bend away and do not enter this area.</u>
How does a magnetic field diagram show where the field is strongest?
- The magnetic field lines do not ever cross.
- The lines include arrowheads to indicate the direction of the force exerted by a magnetic north pole.
- The closer the lines are to the poles, the stronger the magnetic field (thus the magnetic field from a bar magnet is highest closest to the poles).
Where is magnetic field the strongest and weakest on a magnet?
- The bar magnet's magnetic field is strongest at its core and weakest between its two poles.
- The magnetic field lines are densest immediately outside the bar magnet and least dense in the core.
Which two locations on the magnet would have the greatest attractive forces?
- Inside the magnet itself, the field lines run from the south pole to the north pole.
- The magnetic field is strongest in areas of greatest density of magnetic field lines, or areas of the greatest magnetic flux density.
Learn more about magnetic field
brainly.com/question/11514007
#SPJ4