The waste product of photosynthesis is:

Describe how resistance affects the flow of current in a circuit

Sergeu [11.5K]

Resistance decreases the flow of current in a circuit.

Explanation:

The resistance of an electrical circuit is defined as the opposition to the flow of current in that particular circuit

4 0

2 years ago

g Determine the magnitude of the electric field at the surface of a lead-208 nucleus, which contains 82 protons and 126 neutrons

Nookie1986 [14]

Answer:

Explanation:

Electric field at the surface of the the lead 208 = KQ/ R²

where K = 8.99 × 10⁹ Nm² /C²

Q ( total charge inside the nucleus) and e is the charge of a proton = Ne = 82 × 1.6 × 10⁻¹⁹ C = 1.312 × 10⁻¹⁷ C

V of the lead = 208 v of a proton assuming they both are sphere

4/3 πR³ =208( 4/3 πr³) where R is the radius of the sphere and r is the radius of the proton

R³ = 208 r³

R = ∛( 208 r³) = 5.92r

replace r with 1.20 x 10-15 m

R = 5.92 ×1.20 x 10-15 m = 7.11 × 10⁻¹⁵ m

E = ( 8.99 × 10⁹ Nm² /C² × 1.312 × 10⁻¹⁷ C ) / (7.11 × 10⁻¹⁵ m)² = 0.233 × 10²² N/C = 2.33 × 10²¹ N/C

4 0

2 years ago

A ball is thrown horizontally from the top of

stiks02 [169]

I dotn know sorryyyyyyyyyyy

8 0

2 years ago

HELP + extra pts // Two 10-m high diving platforms are at opposing ends of a 30-m pool. How fast must two clowns run straight of

ZanzabumX [31]

Explanation:

The clowns need to leave the diving boards with enough horizontal velocity such that each travels 15 m (half the width of the pool) in the same time that they fall (vertically) the 10-m from the top of the diving board.

We'll assume no force acts on the clowns horizontally to slow them down while they are in flight. And we'll assume that only gravity acts on the clowns vertically.

We can treat the horizontal and vertical components separately. This will help simplify the problem.

Let's start with the vertical displacement. Let's say the clown is dropped from a height of 10-m. How long would it take them to fall that distance?

Using our equations of motion (with constant, linear acceleration), we can solve for this time. $d = vt + \frac{1}{2} at^2$

Where d is the distance travelled, v is the initial velocity, a is acceleration, and t is time.

If the clown is dropped, they have an initial velocity of 0 (zero). We assumed only gravity acts on the clown, so acceleration equals the gravitational acceleration on earth. $a = 9.8m/s^2$

The distance the clown travels is 10-m from the diving board to the surface of the water.

Let's solve. $10 = 0*t + \frac{1}{2} (9.8) t^2 \rightarrow 20/9.8 = t^2 \rightarrow t = \sqrt{20/9.8}$

Now that we know time, we can calculate how fast the clown needs to be running when they leap from the diving board to cover a distance of 15-m (Remember, half the width of the pool.)

Using our equations of motion, we know that $d = vt + 0.5at^2$

We assumed no forces act horizontally on the clown, therefore a = 0. We just need to solve for v. Substituting in the time we just solved for, we get something like this. $15 = v \sqrt{20/9.8}$

I'll leave it to you to solve this equation.

6 0

2 years ago

You take a walk in a rainy night. A street lamp on the corner is mirrored in a puddle of clear water on the ground. In this scen

Dmitriy789 [7]

Answer:

emitting - street lamp, the "source" of the light

transmitting - air and water allow light waves to move through them

absorbing - all the dark surfaces around the street lamp which look dark even when light falls on them

reflecting the light - the puddle of water, which is how a mirror image of the street lamp is formed.

5 0

2 years ago