If this is about simple machines the answer is: Inclined plane
Titty milk I think because it taste amazing so you can go 21km/h
Answer:
The magnitude of the electric force on a protein with this charge is ![7.2\times10^{-15}\ N](https://tex.z-dn.net/?f=7.2%5Ctimes10%5E%7B-15%7D%5C%20N)
Explanation:
Given that,
Electric field = 1500 N/C
Charge = 30 e
We need to calculate the magnitude of the electric force on a protein with this charge
Using formula of electrostatic force
![F=Eq](https://tex.z-dn.net/?f=F%3DEq)
Where, F = force
E = electric field
q = charge
Put the value into the formula
![F=1500\times30\times1.6\times10^{-19}](https://tex.z-dn.net/?f=F%3D1500%5Ctimes30%5Ctimes1.6%5Ctimes10%5E%7B-19%7D)
![F=7.2\times10^{-15}\ N](https://tex.z-dn.net/?f=F%3D7.2%5Ctimes10%5E%7B-15%7D%5C%20N)
Hence, The magnitude of the electric force on a protein with this charge is ![7.2\times10^{-15}\ N](https://tex.z-dn.net/?f=7.2%5Ctimes10%5E%7B-15%7D%5C%20N)
Answer:
Professional education as a science has been defined as a field of educational science that studies the growth of a person into a profession and the related problems. It refers to organized education aimed at the knowledge and skills needed in the profession and working life, as well as growing into active citizenship and membership of society. Professional education as a discipline studies vocational training, skills and learning related to the profession and working life.
It enables young people and adults to pursue goal-oriented learning with the aim of acquiring and developing the necessary skills in the profession and creating the conditions for independent professional activity and continuous development in the profession.
Answer:
ΔE> E_minimo
We see that the field difference between these two flowers is greater than the minimum field, so the bee knows if it has been recently visited, so the answer is if it can detect the difference
Explanation:
For this exercise let's use the electric field expression
E = k q / r²
where k is the Coulomb constant that is equal to 9 109 N m² /C², q the charge and r the distance to the point of interest positive test charge, in this case the distance to the bee
let's calculate the field for each charge
Q = 24 pC = 24 10⁻¹² C
E₁ = 9 10⁹ 24 10⁻¹² / 0.20²
E₁ = 5.4 N / C
Q = 32 pC = 32 10⁻¹² C
E₂ = 9 10⁹ 32 10⁻¹² / 0.2²
E₂ = 7.2 N / C
let's find the difference between these two fields
ΔE = E₂ -E₁
ΔE = 7.2 - 5.4
ΔE = 1.8 N / C
the minimum detection field is
E_minimum = 0.77 N / C
ΔE> E_minimo
We see that the field difference between these two flowers is greater than the minimum field, so the bee knows if it has been recently visited, so the answer is if it can detect the difference