Answer:
light
Explanation:
An abiotic factor is a non-living component in the environment. This can be either a chemical or physical presence. Abiotic factors fall into three basic categories: climatic, edaphic and social. Climatic factors include humidity, sunlight and factors involving the climate. Edaphic refers to soil conditions, so edaphic abiotic factors include soil and geography of the land. Social factors include how the land is being used and water resources in the area. Five common abiotic factors are atmosphere, chemical elements, sunlight/temperature, wind and water.
Temperature and Light

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Temperature of the air and water affect animals, plants and humans in ecosystems. A rise in temperature has the potential to change the way a living thing develops, because it changes the metabolic rate of the organism. All living organisms have a tolerance level for temperature range. For example, a human being would die if he stood out in minus 50 degree temperatures for any length of time. Light exposure often affects the temperature. Areas with direct sunlight are warmer
The correct answer is the loss of genetic variation. This is because after genetic drift, the original poulation of a species decreases in number, and the new dominant genes in the population will live up to reproductive age, and increase the newer genes will thrive.
Answer:
carbon and hydrogen
Explanation:
elements used in the photosintheses
Answer:
CH₄ is the excess reagent and SO₄²⁻ is the limiting reagent.
0.040 g
Explanation:
Step 1: Write the balanced reaction for the methane anaerobic oxidation
CH₄ + SO₄²⁻ ⇒ S²⁻ + CO₂ + 2 H₂O
Step 2: Establish the theoretical mass ratio between the reactants
According to the balanced equation, the theoretical mass ratio of CH₄ to SO₄²⁻ is 16.04:96.06 = 0.1670:1
Step 3: Establish the experimental mass ratio between the reactants
50 mg (0.050 g) of CH₄ react with 60 mg (0.060 g) of SO₄²⁻. The experimental mass ratio of CH₄ to SO₄²⁻ is 0.050:0.060 = 0.83:1
Comparing both mass ratios, we can deduce that CH₄ is the excess reagent and SO₄²⁻ is the limiting reagent.
Step 4: Calculate the mass excess of CH₄
The mass of CH₄ that reacts with 0.060 g of SO₄²⁻ is:
0.060 g SO₄²⁻ 16.04 g CH₄/96.06 g SO₄²⁻ = 0.010 g CH₄
The mass excess of CH₄ is:
0.050 g - 0.010 g = 0.040 g
Answer:
man I need that too are you doing study Island A: A
Explanation: