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KiRa [710]
3 years ago
6

Find the value of x that will make L||M. Please help me!!!!

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Since they are vertical angles.... you have to set them equal to each other so

7x-7= 4x+14

Then you gotta solve it from there.

Subtract 4x to both sides

3x-7=14

Add 7 to both sides

3x=21

divide 3 to both sides

x=3

Hope that this helped you out hon :) BTW YOU ARE SO PRETTY OM FG

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What is the area of this face?
Tju [1.3M]

Answer:

what is your face length

4 0
2 years ago
What is the length of segment AC?<br><br> (Picture attached)
natka813 [3]
6^2 + 8^2 = c^2. \newline&#10;36 + 64 = c^2. \newline&#10;c = \pm10 \Rightarrow AC = 10.
8 0
3 years ago
In the figure below, GRAH is a rectangle, RA=7, and GA=10. Determine AH.
svetoff [14.1K]

Answer:

AH = \sqrt{51}

Step-by-step explanation:

The opposite sides of a rectangle are congruent , so

GH = RA = 7

Using Pythagoras' identity in right Δ GHA

AH² + GH² = GA²

AH² + 7² = 10²

AH² + 49 = 100 ( subtract 49 from both sides )

AH² = 51 ( take the square root of both sides )

AH = \sqrt{51} ≈ 7.14 ( to 2 dec. places )

3 0
3 years ago
Please give me the answer
Lunna [17]

Answer:

37°

Step-by-step explanation:

As we know the sum of angles of a triangle is 180  degrees.

Therefore,

angle A + angle B + angle C = 180°

In the given picture two angles are given and we have to find out the third angle.

x° + 45° + 98° = 180°

x° + 143° = 180°

x° = 180° - 143°

x° = 37°

The value of x in the triangle shown is 37°.

3 0
3 years ago
Which equation is an identity?
Sav [38]

Answer:

Equation 3

Step-by-step explanation:

An identity is, simply put, an equation that is always true. 1 = 1, 2 = 2, and x = x are all examples of identities, as there's no case in which 1 ≠ 1, 2 ≠ 2, and x ≠ x. Essentially, if we can manipulate and equation so that we end up with the same value on either side, we've found an identity. Let's run through and try to solve each of these equations to see which one fulfills that condition:

8 - (6v + 7) = -6v - 1

8 - 6v - 7 = -6v - 1

1 - 6v = -6v - 1

1 = -1

This is clearly untrue. Moving on to the next equation:

5y + 5 = 5y - 6

5 = -6

Untrue again. Solving the third:

3w + 8 - w = 4w - 2(w - 4)

2w + 8 = 4w - 2w + 8

2w + 8 = 2w + 8

If we created a new variable z = 2w + 8, we could rewrite this equation as

z = z, <em>which is always true</em>. We can stop here, as we've now found that equation 3 is an identity.

4 0
3 years ago
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