Answer:Option C:
64 \ cm^2 is the area of the composite figure
It is given that the composite figure is divided into two congruent trapezoids.
The measurements of both the trapezoids are
b_1=10 \ cm
b_2=6 \ cm and
h=4 \ cm
Area of the trapezoid = \frac{1}{2} (b_1+b_2)h
Substituting the values, we get,
A=\frac{1}{2} (10+6)4
A=\frac{1}{2} (16)4
A=32 \ cm^2
Thus, the area of one trapezoid is $32 \ {cm}^{2}$
The area of the composite figure can be determined by adding the area of the two trapezoids.
Thus, we have,
Area of the composite figure = Area of the trapezoid + Area of the trapezoid.
Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2
Thus, the area of the composite figure is 64 \ cm^2
Step-by-step explanation:
Answer:
−
10.5
Step-by-step explanation:
Answer:
I believe the answer is m=30
Step-by-step explanation:
How I got this answer:
first cross multiply
9(m+3) = 11(m-3)
9 m - 11 m = -33 -27
-2m = -60
m= 30 - (Check if the solution is in the defined range).
Answer:
p= 21
Explanation:
FIRST DO
3(21) -7
3 × 21 = 63
63 - 7 = 56
THEN DO
6(21) - 2
6 × 21 = 126
126 - 2 = 124
FINALLY
It needs to add up to 180°
124 + 56 = 180°
Therefore, the value of p = 21
Hope this helps!!! :)
There are few features that you can use to sketch any polynomial function
First is to find x-intercepts of that polynomial. x-intercepts are positions x axis at which function f(x) is equal to 0
Second feature is to find first derivative of the function f(x), make it equal to 0 and again find x values that make first derivative equal to 0. after that implement those x values in f(x) to find f(x) for those values. Now you have sets of (x,y) which are local minimum and maximums of polynomail. Knowing these and with a bit of calculation you can make a decent skecth of any polynomial.
You can also set x=0 to find y- intercept.