This integer is x17, or xx17, or xxx17
all the digits make a sum of 17, ?+1+7=17, ?=9. the other digits need to make a sum of 9
of the numbers from 1-9, only 1 multiplying 7 will result in a 7 in the one's place, so my reasoning is that the ending 17 needs to remain independent, that is, we need to look for the first digits that will make a sum of 9 AND divisible by 17. Keep counting by 17,
17, 34, 51, 68, 85, 102, 119, 136, 153
we can see that the first sum of 9 happens when 17*9=153, 1+5+3=9
so the smallest integer that satisfies all the conditions is 15317
Please let me know if you find another way to figure it out, or if there is a smaller interger
Answer:
x=23
Step-by-step explanation:
The answer is: 1/13
<span>
4 divided by 4 is 1 </span>
<span>and
52 divided by 4 is 13.
:)</span>
Answer:
Step-by-step explanation:
x² + 9x+8 = (x+1)(x+8)
Answer:
x = 1
y = -1
Step-by-step explanation:
A*B= (4y-8 3x-3)
1-) (4×2)+(3×y)= 3y+8
2-) (4×x)+(3×(-1))= 4x-3
AB=C
(3y+8 4x-3)=(5 1)
So
3y+8=5 ; y= -3/3 = -1
4x-3=1 ; x=4/4 =1