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Anna11 [10]
4 years ago
9

A photographer offers a photo shoot for a $85 flat fee. Customers may purchase prints for $5 per sheet. How many sheets can a cu

stomer purchase and spend at most $150? What linear inequality with variable x represents this situation? What is the solution to that inequality? Enter the solution as an inequality using x.
Mathematics
2 answers:
timurjin [86]4 years ago
6 0
Hey user! So we don't know how many sheets they can get with 150$ right? Well I can show you how to do that :)

85(photo shoot) + 5x(5 dollars for every sheet 'x') = 150(maximum amount)

So it'll look like this 

85 + 5x = 150

So subtract 85 from each side

5x = 65

Now divide by 5

x = 13

13 is your answer
Hope this helped!
navik [9.2K]4 years ago
3 0

Answer:

85+5x\leq 150

x\leq 13

Step-by-step explanation:

This is an inequality, so the answers have to be typed out correctly. Proven correct on a test.

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(2w-5)(w+7) so far I got 2w^2 + 9w + ?
FromTheMoon [43]

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=2w2+9w−35

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Aliun [14]

Answer:

Hey


Step-by-step explanation:


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3 years ago
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rusak2 [61]

Answer:

To express percentages in decimal form, you start with the decimal on the right side of the percentage, then you bring the decimal two places to the left. So for example, for 5% it it 5.. when you bring the decimal two places to the left it becomes .05

We start with $371.93 then we multiply each percentage successively to this number

we work backwards

so we start with 5%

$371.93= .95 x X

X=$391.51

Then we take X and do the same process for 10%

$391.51= .90 x Y

Y = $435.01

again we take Y and do the same process for 25%

$435.01= .75 x Z

Z = $580.01

so the original price is $580.01

to find the total percent discount you take the total discounted price ($371.93) divided by the original price ($580.01) then you have 1 subtracted by the number. Finally, you multiply the number by 100 to change it to a percentage

so it's $371.93/$580.01 which = .64125

1 - 64125 = .35875 x 100= 35.88%

so your total percent discount is 35.88%

Hope this helps


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3 years ago
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