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NikAS [45]
3 years ago
14

Kayla paints a bookcase she uses 1 5/6 cups of paint on the outside of the bookcase and 3/8 cup of paint on the inside. How many

cups of paint did Jayla use all together
Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer: Kayla used 2 5/24 cups of paint all together.

Step-by-step explanation:

Kayla paints a bookcase by using

1 5/6 cups of paint on the outside of the bookcase. Converting 1 5/6 cups to improper fraction, it becomes 11/6 cups of paint.

She also used 3/8 cup of paint on the inside.

Therefore, the total number of cups of paint that Kayla used all together would be

11/6 + 3/8 = (44 + 9)/24 = 53/24 cups of paint. Converting to mixed fraction, it becomes

2 5/24 cups of paint

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An angle measures 44° less than the measure of its complementary angle. What is the measure of each angle?
ryzh [129]

a+b=90°

a=b+44°

b+44°+b=90°

2b+44°=90°

2b=90°-44°

2b=46°

b=23°

a=23°+44°

a=67°

8 0
3 years ago
In the Health ABC Study, 543 subjects owned a pet and 1977 subjects did not. Among the pet owners, there were 293 women; 975 of
True [87]

Answer:

The proportion of pet owners who were women is 0.540.

The proportion of non-pet owners who were women is 0.493.

Step-by-step explanation:

The data provided is summarized in the table below.

               Pet Owners      Non-Pet Owners    TOTAL

Men              250                       1002                1252

Women         293                        975                1268

TOTAL          543                       1977                2520

Denote the events as follows:

<em>W</em> = a subject is a women

<em>P</em> = a subject is a pet owner

The probability of an event, say E, is defined as the ration of the favorable outcomes of <em>E</em> to the the total number of outcomes of the experiment.

P (E) = n (E) ÷ N

Here,

n (E) = favorable outcome

N = total number of outcomes

(1)

The conditional probability of an event <em>B</em> given that another events <em>A</em> has already occurred is:

P (B | A) = n (A ∩ B) ÷ n (A)

Compute the probability of a pet owner being a women as follows:

P (W | P) = n (W ∩ P) ÷ n (P)

              = 975 ÷ 1977

              = 0.5396

              ≈ 0.540

Thus, the proportion of pet owners who were women is 0.540.

(2)

Compute the probability of a non-pet owner being a women as follows:

P (W | P') = n (W ∩ P') ÷ n (P')

              = 293 ÷ 543

              = 0.4932

              ≈ 0.493

Thus, the proportion of non-pet owners who were women is 0.493.

8 0
3 years ago
A box contains ten sealed envelopes numbered 1,..., 10. The rst ve contain no money, the next three each contain $5, and there i
Neporo4naja [7]

Answer:

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P(X = 0) = 5/10

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b)

E = 0·5/10 + 5·3/10 + 10·2/10 = 3.5

V = 0^2·5/10 + 5^2·3/10 + 10^2·2/10 - 3.5^2 = 15.25

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1) Which statement is false?A No integers are irrational numbersB All whole numbers are integersC No real numbers are rational n
scoundrel [369]

Answer:

b o\is incorrect

Step-by-step explanation:

b is werpngs

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