All categories

2 years ago

What two pieces of information you need to know velocity

2 answers:

8 0

You need to know the mass of the object and how far it is going or distance then you divide the distance by the time to get the velocity.

amid [387]2 years ago

4 0

You need to know mass and speed

1. rate of change of position this is measured in m/s
2. direction in change of position.

You might be interested in

A 25-ft ladder and then you can get inside of a house the bottom of the ladder is 8 ft away from the bottom of the house what is

seropon [69]

Answer:

$71.33$ degree

Step-by-step explanation:

The angle between the bottom of the ladder and the ground is given by

$cos\alpha = \frac{B}{L}$

Where

B = distance between wall of house and the foot of ladder

L = Length of the ladder

Substituting the given values we get -

$Cos \alpha = \frac{8}{25}\\Cos \alpha = 0.32\\\alpha = Cos^{-1}(0.32)\\\alpha = 71.33$

4 0

3 years ago

Help please!!!!!!!!!

devlian [24]

Answer:

YOU not smartYOU DONT KNOW THIS HA HA NOT HELPING YOU BOT.

Step-by-step explanation:

4 0

2 years ago

A tank has the shape of a surface generated by revolving the parabolic segment y = x2 for 0 ≤ x ≤ 3 about the y-axis (measuremen

Darina [25.2K]

Answer:

$100\pi\int\limits^9_0 {(\sqrt y)^2(14-y)} \, dy$ ft-lbs.

Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving $y=x^2$ about y axis in the interval $0\leq x\leq 3$ .

Density of the fluid in the tank, $D=100\ lbs/ft^3$

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, $y(0)=0^2=0$

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in $x=3$ in the parabolic equation . This gives,

$H=3^2=9\ ft$

So, the height of top of tank is, $y(3)=H=9\ ft$

Now, 5 ft above 'H' means $H+5=9+5=14$

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

$\Delta y=(14-y)$ ft

Now, area of cross section of the tank is given as:

$A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section$

Radius is the distance of a point on the parabola from the y axis. This is nothing but the x-coordinate of the point.

We have, $y=x^2$

So, $x=\sqrt y$

Therefore, radius, $r=\sqrt y$

Now, area of cross section is, $A(y)=\pi (\sqrt y)^2$

Work done in pumping the contents to 5 feet above is given as:

$W=D\int\limits^{y(3)}_{y(0)} {A(y)(\Delta y)} \, dy$

Plug in all the values. This gives,

$W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}$

7 0

2 years ago

(01.03)

Zielflug [23.3K]

The dimensions of the paint tray are:
W = 10 in
L = 12 in
D = 5 cm (1in / 2.54 cm) = 1.97 in

The total volume of the paint tray is:
Vt = WLD
Vt = (10)(12)(1.97) = 236.22 in3

Converting the volume of the paint to in3
Vp = 1 gal (231 in3 / 1gal) = 231 in3

Getting the difference,
236.22 in3 - 231in3 = 5.22 in3

Since the volume of tray is greater than the volume of the paint, the answer is:
The paint will not fill the tray by 5.22 in3.

6 0

2 years ago

Adrienne can make of a bracelet in hour. How many bracelets can she make in 1 hour?

Bess [88]

<span>Adrienne can make of a bracelet in hour

so 1 bracelet in 1 hour

answer: </span><span>1 bracelet</span>

3 0

3 years ago

Read 2 more answers