The sum of 3 consecutive even numbers is 42.Find the largest number.
2 answers:
Let the smallest number among them is n then next two consecutive even terms are: n+2 and n+4 The sum of numbers is 42, so: ↪n+n+2+n+4=42 ↪3n+6=42 ↪3n=42-6 ↪n=36/3 ↪n=12 The largest among these numbers is : n+4 =12+4 =16↪Answer
<u>Define x: </u> Let the smallest number be x The other 2 numbers are x+2 and x+4 <u>Construct Equation: </u> Sum of the numbers is 42 ⇒x + (x + 2) + (x + 4) = 42 <u>Solve for x: </u> x + (x + 2) + (x + 4) = 42 Remove brackets: x + x + 2 + x + 4 = 42 Combine like terms: 3x + 6 = 42 Subtract 6 from both sides: 3x = 36 Divide both sides by 3: x = 12 <u>Find largest number: </u> The largest number = x + 4 = 12 + 4 = 16Answer: The largest number is 16.
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