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Troyanec [42]
3 years ago
13

The sum of 3 consecutive even numbers is 42.Find the largest number.

Mathematics
2 answers:
algol133 years ago
6 0
Let the smallest number among them is n then next two consecutive even terms are: n+2 and n+4

The sum of numbers is 42, so:

↪n+n+2+n+4=42
↪3n+6=42
↪3n=42-6
↪n=36/3
↪n=12

The largest among these numbers is :
n+4
=12+4
=16↪Answer
Tom [10]3 years ago
6 0
<u>Define x:
</u>
Let the smallest number be x
The other 2 numbers are x+2 and x+4

<u>Construct Equation:
</u>
Sum of the numbers is 42
⇒x + (x + 2) + (x + 4) = 42

<u>Solve for x:
</u>
x + (x + 2) + (x + 4) = 42

Remove brackets:
x + x + 2 + x + 4 = 42

Combine like terms:
3x + 6 = 42

Subtract 6 from both sides:
3x = 36

Divide both sides by 3:
x = 12

<u>Find largest number:
</u>
The largest number = x + 4  = 12 + 4  = 16

Answer: The largest number is 16.

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