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Troyanec [42]
4 years ago
13

The sum of 3 consecutive even numbers is 42.Find the largest number.

Mathematics
2 answers:
algol134 years ago
6 0
Let the smallest number among them is n then next two consecutive even terms are: n+2 and n+4

The sum of numbers is 42, so:

↪n+n+2+n+4=42
↪3n+6=42
↪3n=42-6
↪n=36/3
↪n=12

The largest among these numbers is :
n+4
=12+4
=16↪Answer
Tom [10]4 years ago
6 0
<u>Define x:
</u>
Let the smallest number be x
The other 2 numbers are x+2 and x+4

<u>Construct Equation:
</u>
Sum of the numbers is 42
⇒x + (x + 2) + (x + 4) = 42

<u>Solve for x:
</u>
x + (x + 2) + (x + 4) = 42

Remove brackets:
x + x + 2 + x + 4 = 42

Combine like terms:
3x + 6 = 42

Subtract 6 from both sides:
3x = 36

Divide both sides by 3:
x = 12

<u>Find largest number:
</u>
The largest number = x + 4  = 12 + 4  = 16

Answer: The largest number is 16.

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15. Ankita bought 20 copy for Rs. 25 each. She got profit of Rs.200 while selling it. Find selling price of the copies. no​
goblinko [34]

Answer:

SP=Rs.700

Step-by-step explanation:

<em>cost</em><em> </em><em>price</em><em> </em><em>of a</em><em> </em><em>copy</em><em>=</em><em>R's</em><em>.</em><em>2</em><em>5</em>

<em>cost price of</em><em> </em><em>2</em><em>0</em><em>c</em><em>o</em><em>p</em><em>y</em><em>=</em><em>2</em><em>0</em><em>×</em><em>2</em><em>5</em><em>=</em><em>R</em><em>s</em><em>.</em><em>5</em><em>0</em><em>0</em>

<em>profit</em><em>=</em><em>Rs</em><em>.</em><em>2</em><em>0</em><em>0</em>

<em>selling</em><em> </em><em>price</em><em> </em><em>of</em><em> </em><em>2</em><em>0</em><em> </em><em>copies</em><em>=</em><em>?</em>

<em>Now</em><em>,</em><em> </em><em>we</em><em> </em><em>know</em><em> </em><em>that</em><em>,</em><em> </em>

<em>profit</em><em>=</em><em>sp-cp</em>

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