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pishuonlain [190]
3 years ago
15

Find the sum of -2x^ - 3x and x^ + 7x

Mathematics
1 answer:
vichka [17]3 years ago
5 0
Sum of -2x^-3x is -5x and sum of x^+7x is 8x hope this helps answer my question please !!
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A square can be. Rhombus, and figure X is a rhombus, so figure X must be a square. True or false
kvasek [131]
I have to go with True because a Rhombus is a Square. 
3 0
3 years ago
Read 2 more answers
bru you just times the too numbers then you divide the answer by 2 then you times that by 4 then that your answer BIG BRAIN 1694
Salsk061 [2.6K]

Answer: SHEEEESHOOOOOO yesssirrrr big brainnnnnnn :clap clap:

6 0
2 years ago
HURRY! Point H is the circumcenter of triangle JKL. Which must be true?
pav-90 [236]
A circumcentre is the centre of the circumcircle.  
The circumcircle of a triangle is the circle that passes through all three vertices.

Since all radii of a given circle are equal, we see that all the distances from H (circumcentre) to the vertices of the triangle are equal, namely
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7 0
4 years ago
Help me please i will mark brainliest if correct
aksik [14]

Answer:

-11

8 = 2x + 30

8 - 30 = -22

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x = -11

Also if you place 2×(-11) + 30 you get 8

8 0
3 years ago
You fly a hot air balloon 3.5 miles above the ground. What is the measure of BD⌢, the portion of Earth that you can see? Round y
STatiana [176]

Answer:

\Delta s \approx 334.545\,m

Step-by-step explanation:

Let assume that Earth is a sphere, the following trigonometric diagram is constructed and presented below. The central angle is given by this inverse trigonometric equation:

\theta = 2\cdot \cos^{-1} \left(\frac{r}{r+h} \right)

\theta = 2\cdot \cos^{-1}\left(\frac{4000\,mi}{4000\,mi+3.5\,mi} \right)

\theta = 4.792^{\circ}

The distance of the portion of Earth that can be seen is:

\Delta s = \frac{4.792^{\circ}}{360^{\circ}}\cdot (2\pi)\cdot (4000\,mi)

\Delta s \approx 334.545\,m

7 0
3 years ago
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