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bearhunter [10]
3 years ago
15

An induced emf is produced inA. a closed loop of wire when it remains at rest in a nonuniform static magnetic field.B. a closed

loop of wire when it remains at rest in a uniform static magnetic field.C. a closed loop of wire moving at constant velocity in a nonuniform static magnetic field.D. only b and c above.E. all of the above.
Physics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

C. a closed loop of wire moving at constant velocity in a nonuniform static magnetic field.

Explanation:

As we know by Faraday's law that rate of change in magnetic flux will induce EMF

so mathematically we can say that

EMF = \frac{d\phi}{dt}

so we will have

\phi = B.A

so EMF will be induced if the flux linked with the closed loop will change with time.

So here correct answer will be

C. a closed loop of wire moving at constant velocity in a nonuniform static magnetic field.

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Explanation:

This exercise the system is formed by platform, man and bricks; For this system, when the bricks are released, the forces are internal, so the kinetic moment is conserved.

Let's write the moment two moments

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       L₀ = I₁ w₁

final moment. After releasing the bricks

       L_{f} = I₂W₂

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       I₁ w₁ = I₂ w₂

       w₂ = I₁ / I₂ w₁

let's reduce the data to the SI system

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       w₂ = 6.0/2.0   7.54

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A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
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The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

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Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

  • Finally, we shall determine the acceleration of the crate

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Learn more on friction: brainly.com/question/364384

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