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bearhunter [10]
3 years ago
15

An induced emf is produced inA. a closed loop of wire when it remains at rest in a nonuniform static magnetic field.B. a closed

loop of wire when it remains at rest in a uniform static magnetic field.C. a closed loop of wire moving at constant velocity in a nonuniform static magnetic field.D. only b and c above.E. all of the above.
Physics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

C. a closed loop of wire moving at constant velocity in a nonuniform static magnetic field.

Explanation:

As we know by Faraday's law that rate of change in magnetic flux will induce EMF

so mathematically we can say that

EMF = \frac{d\phi}{dt}

so we will have

\phi = B.A

so EMF will be induced if the flux linked with the closed loop will change with time.

So here correct answer will be

C. a closed loop of wire moving at constant velocity in a nonuniform static magnetic field.

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Answer:

1)Fuel Sourcing

2)Power Generation

Explanation:

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2)Power Generation: Fossil fuels must be burned to produce electricity. Burning them creates unwanted byproducts that can create air and water pollution and release huge amounts of greenhouse gasses into the atmosphere.

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3 years ago
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A circuit has a current of 1.2 A. If the voltage decreases to one third of its original amount while the resistance remains cons
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When resistance is constant, current is proportional to voltage. When 1/3 the voltage is applied, 1/3 the current will result.

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The resulting current will be 0.4 A.
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3 years ago
Describe your acceleration as you skate down your neighborhood sidewalk.
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Answer: when you increase or decrease your speed.

Explanation:

Moving a skate at rest, you need to apply force in order to cause acceleration.

F = ma Where

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a = acceleration

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as you skate down your neighborhood sidewalk, you will accelerate when you increase your speed. Because

Acceleration is the rate of change of velocity. That is,

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3 years ago
How can Newton's third law describe the forces affecting a rocket as it
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Apex

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3 years ago
If the gas inside the flask in the above exercise is cooled so that its pressure is reduced to a value of 715.7 torr, what will
evablogger [386]

Answer:

(a) 49.0 mm

Explanation:

#First we need to calculate the height of the mercury arm:

Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:

P_g_a_s=P_a_t_m+P_h\\  

The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.

P_g_a_s=P_a_t_m+P_h\\797.3=P_a_t_m+(136.4mm-103.8mm)\\P_a_t_m=764.7mm\\\\h_t_o_t_a_l=136.4mm+103.8mm=240.2mm\\\\P_g_a_s=P_a_t_m+\bigtriangleup h\\\bigtriangleup h=P_g_a_s-P_a_t_m\\\\\bigtriangleup h=715.7mm-764.7mm\\=-49mm

Hence the height of the mercury in the arm is 49.00mm

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3 years ago
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