Answer:
Force = 21.85N
Explanation:
Given the following data;
Mass = 2.3kg
Acceleration = 9.5m/s²
To find the force;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Substituting into the equation, we have
Force = 2.3 * 9.5
Force = 21.85N
Therefore, the force applied to the rat is 21.85 Newton.
Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;
Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.