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kirza4 [7]
3 years ago
6

PLEASE HELP ASAP!!!

Physics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

B - Velocity

Explanation:

Velocity definition: “The speed of something in a given direction.”

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a mass m at the end of a spring oscillates with a frequency of 0.78 hz . when an additional 730 g mass is added to m, the freque
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The value of mass m = 0.506kg

Initial frequency = 0.78Hz

additional mass =  730 g = 0.73kg

New frequency = 0.65 Hz

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additional mass,

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mass m = 0.506kg

a measurement used in physics to express the inertia, a quality that all matter has in common. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilograms is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one kilogramme times one square metre per second. The kilogramme is determined by precise measurements of Planck's constant, while the second and metre are already defined in terms of other physical constants.

Learn more about mass here:

brainly.com/question/506625

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4 0
1 year ago
What substance is the genetic material of living things?
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I believe it's DNA.
Here're some sentences to explain:

Genetic material, also known as deoxyribonucleic acid<span> (</span>DNA<span>) and </span>Ribonucleic acid<span> (</span>RNA<span>), plays a fundamental role in the composition of living organisms.</span>
3 0
3 years ago
A constant torque is applied to a rigid wheel whose moment of inertia is 2.0 kg · m2 around the axis of rotation. If the wheel s
Jlenok [28]

Answer:

The applied torque is 3.84 N-m.      

Explanation:

Given that,

Moment of inertia of the wheel is 2\ kg-m^2

Initial speed of the wheel is 0 (at rest)

Final angular speed is 25 rad/s

Time, t = 13 s

The relation between moment of inertia and torque is given by :

\tau=I\alpha \\\\\tau=I\times \dfrac{\omega_f}{t}\\\\\tau=2\times \dfrac{25}{13}\\\\\tau=+3.84\ N-m

So, the applied torque is 3.84 N-m.

4 0
3 years ago
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