Answer:
V_inside = 36 V
Explanation:
<u>Given </u>
We are given a sphere with a positive charge q with radius R = 0.400 m Also, the potential due to this charge at distance r = 1.20 m is V = 24.0 V.
<u>Required</u>
We are asked to calculate the potential at the centre of the sphere
<u>Solution</u>
The potential energy due to the sphere is given by equation
V = (1/4*π*∈o) × (q/r) (1)
Where r is the distance where the potential is measured, it may be inside the sphere or outside the sphere. As shown by equation (1) the potential inversely proportional to the distance V
V ∝ 1/r
The potential at the centre of the sphere depends on the radius R where the potential is the same for the entire sphere. As the charge q is the same and the term (1/4*π*∈o) is constant we could express a relation between the states , e inside the sphere and outside the sphere as next
V_1/V_2=r_2/r_1
V_inside/V_outside = r/R
V_inside = (r/R)*V_outside (2)
Now we can plug our values for r, R and V_outside into equation (2) to get V_inside
V_inside = (1.2 m )/(0.600)*18
= 36 V
V_inside = 36 V
Answer:
I'm pretty sure it shows a direct relationship
Explanation:
The answer is mass and acceleration
Answer:
Newton's Third Law of Motion
Explanation:
it explains that forces always come in action-reaction pairs. The Third Law states that for every action force, there is an equal and opposite reaction force
Answer is Option C
hope it helps you
