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3 years ago

What happens to warm air when it cools?

Physics

2 answers:

MrMuchimi3 years ago

7 0

Answer:

I think the answer is B

Explanation:

The warm air turns cold and then it goes back to clouds

wolverine [178]3 years ago

4 0

Answer:

b I'm pretty sure sorry if I'm wrong

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g You are blowing air into a spherical balloon at a rate of 33 cubic inches per second. Given that the radius of the balloon is

Marina CMI [18]

Answer:

$\frac{3}{16\pi}in/sec$

Explanation:

We are given that

$\frac{dv}{dt}=3in^3/s$

r=2 in when t=4 s

We have to find the rate of change of radius.

We know that

Volume of sphere= $V=\frac{4}{3}\pi r^3$

Differentiate w.r.t t

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the values

$3=4\pi(2)^2\times \frac{dr}{dt}$

$\frac{dr}{dt}=\frac{3}{4\pi(2)^2}$

$\frac{dr}{dt}=\frac{3}{16\pi}in/sec$

8 0

3 years ago

100 points to whoever can help, please

Shkiper50 [21]

Answer:

A) 1.2x10^5 J

Explanation:

6 0

3 years ago

A monkey (mass m) is swinging on a vine of length L while carrying a bunch of bananas (a large bunch, mass m/2). His swinging mo

dmitriy555 [2]

Answer:

Explanation:

The period of oscillation will remain unchanged because the period of oscillation of a pendulum does not depend upon the mass of the bob . Here monkey along with bunch of banana represents bob .

When the monkey and banana were at height h /2 , they have potential energy as well as kinetic energy . banana is separated from the system . It carried its total energy along with it . But the energy of monkey remained intact with it . So it will keep on moving as usual . So it will attain the same maximum height as before .

Hence the amplitude of oscillation too will remain unchanged .

6 0

3 years ago

Car A has a mass of 1,000 kg and is traveling 60 km/hr. Car B has a mass of 2,000 kg and is traveling 30 km/hr. Compare the kine

Artyom0805 [142]

Answer:

c) Twice as much

Explanation:

As we know that kinetic energy is given by the formula

$K = \frac{1}{2}mv^2$

here we know that

m = mass of the object

v = speed of the object

so here we will have kinetic energy of Car A

$K = \frac{1}{2}(1000)(60^2)$

$K_a = 1.8 \times 10^6$

now we have kinetic energy of B is given as

$K_b = \frac{1}{2}(2000)(30^2)$

$K_b = 0.9 \times 10^6$

So kinetic energy of Car A is double that of Kinetic energy of car B

3 0

4 years ago

Read 2 more answers

In 0.601 s, a 13.1-kg block is pulled through a distance of 4.19 m on a frictionless horizontal surface, starting from rest. The

Naya [18.7K]

Answer:

0.615 m

Explanation:

We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.

The acceleration is determined using the equation of motion.

Given parameters:

Initial velocity, u = 0.00 m/s

Distance, s = 4.19 m

Time, t = 0.601 s

We use the equation

$s = ut+\frac{1}{2}at^2$