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3 years ago

Find the sum of the first 9 terms in the following geometric series 7+21+63+

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer: 68887

Step-by-step explanation: the geometics series is (the previous number in the series) x 3, so 63 x 3 =189 x 3 =567 x 3 = 1701 x 3 = 5103 x 3 =15309 x 3 = 45927 and you add all those numbers up to get 68887

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3 years ago

A geometric series that starts with 2, ends with -6250 and has a common ratio of -5

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3 years ago

Arrange the systems of equations that have a single solution in increasing order of the x-values in their solutions. 2x + y = 10

Sladkaya [172]

Answer: 4,0,2

Step-by-step explanation:

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3 years ago

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Which pair of angles shares ray A.F as a common side? DAF and DAB EAF and CAE BAF and EAD BAF and FAD

shtirl [24]

Answer:

BAF and FAD

Step-by-step explanation:

In order for an angle to have A.F as a side, it must have the letters A.F or FA in its name.

In DAF, the angle is made of rays AD and A.F. In DAB, the angle is made up of rays AD and AB. This is not the correct pair.

In EAF, the angle is made of rays AE and A.F. In CAE, the angle is made up of rays AC and AE. This is not the correct pair.

In BAF, the angle is made of rays AB and A.F. In EAD, the angle is made up of rays AE and AD. This is not the correct pair.

In BAF, the angle is made up of rays AB and A.F. In FAD, the angle is made up of rays A.F and AD. This is the correct pair.

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3 years ago

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Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min

leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2}$ .

First, we simplify the expression in the numerator of the fraction.

$3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72$

Now, we obtain

$12(x^2-x-6) = 12(x+2)(x-3)$

and the fraction is transformed into

$\frac{3(2x-1)^2 - 75}{x+2} = \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)$

Therefore, the following limit is

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2} 12(x-3) = 12 \lim_{x \to -2} (x-3)$

You can plug in $-2$ in the equation, hence

$12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60$

6 0

4 years ago