Answer:
$24.35
Step-by-step explanation:
We will use the compound interest formula provided to solve this problem:
<em>P = initial balance</em>
<em>r = interest rate (decimal)</em>
<em>n = number of times compounded annually</em>
<em>t = time</em>
<em />
First, change 1% into a decimal:
1% -> 
-> 0.01
Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:
Lastly, subtract <em>A </em>from the principal to get the interest earned:
M
=
0
O
r
m
=
23
15
Explanation:
1
3
m
+
6
m
−
9
3
m
=
3
m
−
3
4
m
⇒
1
+
6
m
−
9
3
m
=
3
m
−
3
4
m
⇒
−
8
+
6
m
3
m
=
3
m
−
3
4
m
⇒
(
−
8
+
6
m
)
×
4
m
=
(
3
m
−
3
)
×
3
m
⇒
−
32
m
+
24
m
2
=
9
m
2
−
9
m
⇒
−
32
m
+
24
m
2
−
9
m
2
+
9
m
=
0
⇒
15
m
2
−
23
m
=
0
⇒
m
(
15
m
−
23
)
=
0
m
=
0
Or
15
m
−
23
=
0
⇒
15
m
=
23
⇒
m
=
23
15
Answer:
x ≤ 3
Step-by-step explanation:
11
x
−
20
≤
13
Step 1: Add 20 to both sides.
11
x
−
20
+
20
≤
13
+
20
11
x
≤
33
Step 2: Divide both sides by 11.
11
x
11
≤
33
11
Answer:
(25,18) is the required solution.
Step-by-step explanation:
We are given the following in the question:
Let x be the number of trips to the airport and y represent the number of trips from the airport.
Total number of fares to and from the airport = 43
Thus, we can write the equation:
Price for a ride to the airport = $12
Price for a ride from the airport = $10
Total amount collected by the driver = $480
Thus, we can write the equation:
Solving the two equations, we get,
Thus, the driver made 25 trips to the airport and 18 trips from the airport.
The solution can be represented as (25,18)
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
