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3 years ago

Write the following equation in the general form Ax + By + C = 0. 2x + y = 6

Mathematics

1 answer:

katen-ka-za [31]3 years ago

5 0

<span>2x + y = 6
2x + y - 6 = 0

answer is </span>2x + y - 6 = 0

hope that helps

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Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

Read 2 more answers

Plsssssssssss just helppppp

yan [13]

Answer:

Step-by-step explanation:

The missing length is 10-4 = 6

Therefore perimeter = 5 + 6 + 8+ 4+13 +10

=46

3 0

3 years ago

How would you solve this

nika2105 [10]

To find 10% you would just divide 200 by 10
=200/10
=20

hope this helped !

3 0

3 years ago

I don't understand how to solve this, please help!

murzikaleks [220]

Answer:

x+1 , x<-1

x²-bx-4 , -1≤x≤4

1/2 x +a

substitute x=-1 , continuous everywhere

x+1=x²-bx-4 when x=-1

-1+1=-1²-b-4

then for :

x²-bx-4=1/2 x +a for x=4

4²-4b-4=1/2x+a

16-4(3)-4=4/2+a

16-12-4-2=a

the equations will be :

x+1

x²-3x-4

1/2x-2

I hope this help

7 0

3 years ago

Without multiplying, tell which is greater: x 45 or x 45 explain.

Vanyuwa [196]

Answer: x45=x45 cannot be greater because they're both equivalent to each other.

Step-by-step explanation:

6 0

3 years ago