Directly proportional to x.
<h3>What is propotionality?</h3>
- In algebra, proportionality is the equality of two ratios.
- A and B are in the same ratio as C and D in the formula a/b = c/d.
- When one of a proportion's four quantities is unknown, a proportion is often built up to resolve the word problem.
- By multiplying one numerator by the opposing denominator and equating the result to that of the other numerator and denominator, the equation can be solved.
- Any relationship that has a constant ratio is said to be proportionate. For instance, the ratio of proportionality is the average number of apples per tree, and the amount of apples in a crop is proportional to the number of trees in the orchard.
Acc to our question-
- If two variables' ratios (yx)
- (x and y) have the same value as a constant (k=yx)
- therefore the ratio's variable (y) in the numerator is the sum of the other variable and the constant (y=k:x).
- With a proportionality constant of k, it is claimed that y is directly proportional to x in this instance.
Hence,Directly proportional to x.
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Answer:
C. 1,3,5,7,9
Step-by-step explanation:
The domain is all of the values of x.
So, in this case, the domain is 1,3,5,7,9.
-hope it helps
Answer:
a) (0.806, 0.852)
b)Margin of error ≤ 0.01
1.96*√{0.5*(1–0.5)/n} ≤ 0.01
√n ≥ 98
n ≥ 9604
• Smallest sample size = 9604
Step-by-step explanation:
I found this on Chegg
I think it's a, c or e since those are all close to ten but you could use a ruler
Answer:
the balls are larger, or don't pack as tightly
Step-by-step explanation:
The volume by either measure will depend on a couple of factors:
- the volume of the unit used (ball or cube)
- the way the units can be packed
In a rectangular space, such as a box, it may be easier to pack cubes than balls. So, more cubes of the same volume would fit simply because they can be packed closer together.
We aren't told the volume of either the cube or the ball, and we're not told the extent to which the packing is optimized.
Fewer balls may fit because their packing is not as well optimized as that of the cubes, or because each has a larger volume than the cube being used.
