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Fofino [41]
3 years ago
11

3=g/-4-5 solve for g

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

4

Step-by-step explanation:

so first you write down the problem and substitute the g by 3 after that you subtract

3 - 4 = 1 - 5 = 4

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Find three consecutive even integers such that 27 more than 3 times the second is 7 less than 8 times the first
White raven [17]

Answer:

The three consecutive even integers are 8, 10 and 12.

Step-by-step explanation:

Let the three consecutive even integers be x, x+2, x+4

The statement "27 more than 3 times the second is 7 less than 8 times the first" can be expressed as:

27+3(x+2)=8x-7

Solve this expression for <em>x</em> as follows:

27+3(x+2)=8x-7\\27+3x+6=8x-7\\33+3x=8x-7\\40=5x\\x=8

The three consecutive even integers are:

x=8\\x+2=8+2=10\\x+4=8+4=12

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3 years ago
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7 0
3 years ago
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How do I solve this problem
VladimirAG [237]
Hi there!

Since, The length of th' tangents drawn from an external point to a circle are equal.

Therefore, we draw following conclusions :-

• CF = EC = 6 cm
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Now,

According to th' question, Perimeter of ΔΑΒC :-

AB + BC + AC

⇒ AD + DB + BE + EC + CF + FA

⇒ 12 cm + 16 cm + 16 cm + 6 cm + 6 cm + 12 cm = 68 cm

Hence,
The Perimeter of ΔΑΒC is 68 cm

~ Hope it helps!
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Answer:

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