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Fofino [41]
3 years ago
11

3=g/-4-5 solve for g

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

4

Step-by-step explanation:

so first you write down the problem and substitute the g by 3 after that you subtract

3 - 4 = 1 - 5 = 4

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What is this simplified? Please help
Naya [18.7K]

Answer:

The end result is -1/(x + 1)

Step-by-step explanation:

In order to find the answer to this, we first need to factor the denominator. Since it is a quadratic, we try to find number that multiply to the last term (8) and add to the middle term (9). In this case, the numbers 8 and 1 would work. This allows us to use those numbers in parenthesis along with x as a fully factored form.

x^2 + 9x + 8 = (x + 1)(x + 8)

Now that we have this factored we can take the original equation and factor a -1 out of the top.

(-1)(x + 8)/(x + 1)(x + 8)

Since there is an (x + 8) on the top and bottom, we can cancel those.

-1/(x + 1)

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3 years ago
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Answer:

rn or later?

Step-by-step explanation:

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vlada-n [284]
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DaniilM [7]
1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
(x_{1},y_{1}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point
Length of  WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}
d_{WZ}= \sqrt{(3)^2+(2)^2}
d_{WZ}= \sqrt{9+4}
d_{WZ}= \sqrt{13}

We know that all the sides of a rhombus have the same length, so 
d_{YZ}=  \sqrt{13}
d_{XY}= \sqrt{13}
d_{XW}= \sqrt{13}

Now, we just need to add the four sides to get the perimeter of our rhombus:
perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}
perimeter=4 \sqrt{13}
We can conclude that the perimeter of our rhombus is 4 \sqrt{13} square units. 

2. To solve this, we are going to use the arc length formula: s=r \alpha
where
s is the length of the arc. 
r is the radius of the circle.
\alpha is the central angle in radians

We know form our problem that the length of arc PQ is \frac{8}{3}  \pi inches, so s=\frac{8}{3} \pi, and we can infer from our picture that r=15. Lest replace the values in our formula to find the central angle POQ:
s=r \alpha
\frac{8}{3} \pi=15 \alpha
\alpha =  \frac{\frac{8}{3} \pi}{15}
\alpha = \frac{8}{45} \pi

Since \alpha =POQ, We can conclude that the measure of the central angle POQ is \frac{8}{45} \pi

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut  in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section. 
We can conclude that the draw of our cross section is:

6 0
3 years ago
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