Answer:
one dimension of motion on a circle is "back and forth"
Explanation:
Whether the position graphs look the same or not is a function of the acceleration (and velocity), and how position is measured.
For a circle centered at the origin, uniform motion around the circle will be equivalent to sinusoidal motion in the x- or y-directions. So, that motion is equivalent to sinusoidal motion "back and forth", however it may be generated.
The "back and forth" motions of a piston in a cylinder (connected to a crankshaft), and of a pendulum, are almost sinusoidal, but not quite. Their position graphs will differ slightly from the graph of position of an object moving around a circle.
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On the other hand, if the circular motion is plotted as the length of the radius versus time, it will be a constant -- not "back and forth" at all.
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In short, plots of similar motion will look similar.
Distance = 1/2*gravity*velocity^2
<span>So plugging: 1/2 * 9.8 * 25 = 122.5units
and is six second
</span><span>Distance = 1/2*gravity*velocity^2
</span><span>So plugging: 1/2 * 9.8 * 36= 176.4 units</span>
Answer: The force is directed upward
Explanation: Considering the Lorentz force, given by:
F= qv×B
using the right hand rule and considering the direction of electron velocity and the magnetic field from the figure, the vectorial product gives a force vector upwards .
Answer:
h= 45.87 m.
Explanation:
Data given:
Vf= 30m/s , and we know that g = 9.8 m/s²
The ball has an initial velocity of zero Vi = 0 m/s²
To Find:
Height of the building = ?
Solution:
According to 3rd law of the motion;
2aS= Vf² - Vi² ( S= h , a=g)
2*9.81*h = (30)² - (0)²
h= 45.87 m.
The period of the wave is the reciprocal of its frequency.
1 / (5 per second) = 0.2 second .
The wavelength is irrelevant to the period. But since you
gave it to us, we can also calculate the speed of the wave.
Wave speed = (frequency) x (wavelength)
= (5 per second) x (1cm) = 5 cm per second
