The gravitational force between the objects A. It would increase.
Explanation:
The magnitude of the gravitational force between two objects is given by:
![F=G\frac{m_1 m_2}{r^2}](https://tex.z-dn.net/?f=F%3DG%5Cfrac%7Bm_1%20m_2%7D%7Br%5E2%7D)
where
G is the gravitational constant
are the masses of the two objects
r is the separation between the objects
In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of
increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.
Therefore, the correct answer is
A. It would increase.
Learn more about gravitational force:
brainly.com/question/1724648
brainly.com/question/12785992
#LearnwithBrainly
Answer: ![5.9(10)^{-8} m](https://tex.z-dn.net/?f=5.9%2810%29%5E%7B-8%7D%20m)
Explanation:
The equation to calculate the center of mass
of a particle system is:
![C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}](https://tex.z-dn.net/?f=C_%7BM%7D%3D%5Cfrac%7Bm_%7B1%7Dr_%7B1%7D%2Bm_%7B1%7Dr_%7B1%7D%2B...%2Bm_%7Bn%7Dr_%7Bn%7D%7D%7Bm_%7B1%7D%2Bm_%7B2%7D%2B...%2Bm_%7Bn%7D%7D)
In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:
![C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}](https://tex.z-dn.net/?f=C_%7BM%7D%3D%5Cfrac%7Bm_%7BE%7D%280%20m%29%20%2B%20m_%7Bp%7D%20r_%7BE-p%7D%7D%7Bm_%7BE%7D%2Bm_%7Bp%7D%7D)
Where:
is the mass of the Earth
is the mass of 1 billion people
is the radius of the Earth
is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)
![C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}](https://tex.z-dn.net/?f=C_%7BM%7D%3D%5Cfrac%7Bm_%7Bp%7D55%2810%29%5E%7B9%7D%20kg%20%286370998%20m%29%7D%7B5.9%2810%29%5E%7B24%7D%20kg%2B55%2810%29%5E%7B9%7D%20kg%7D)
This is the displacement of Earth's center of mass from the original center.
Answer:
![f=140\ N](https://tex.z-dn.net/?f=f%3D140%5C%20N)
Explanation:
Given:
- mass of the object on a horizontal surface,
![m=50\ kg](https://tex.z-dn.net/?f=m%3D50%5C%20kg)
- coefficient of static friction,
![\mu_s=0.3](https://tex.z-dn.net/?f=%5Cmu_s%3D0.3)
- coefficient of kinetic friction,
![\mu_k=0.2](https://tex.z-dn.net/?f=%5Cmu_k%3D0.2)
- horizontal force on the object,
![F=140\ N](https://tex.z-dn.net/?f=F%3D140%5C%20N)
<u>Now the value of limiting frictional force offered by the contact surface tending to have a relative motion under the effect of force:</u>
![F_s=\mu_s.N](https://tex.z-dn.net/?f=F_s%3D%5Cmu_s.N)
where:
normal force of reaction acting on the body= weight of the body
![F_s=0.3\times (50\times 9.8)](https://tex.z-dn.net/?f=F_s%3D0.3%5Ctimes%20%2850%5Ctimes%209.8%29)
![F_s=147\ N](https://tex.z-dn.net/?f=F_s%3D147%5C%20N)
As we know that the frictional force acting on the body is always in the opposite direction:
So, the frictional force will not be at its maximum and will be equal in magnitude to the applied external force and hence the body will not move.
so, the frictional force will be:
![f=140\ N](https://tex.z-dn.net/?f=f%3D140%5C%20N)
Answer:
Explanation:
v = u +at
u = 0
a = 2.3 m /s²
t = 20 s
v = 2.3 x 20
= 46 m /s
Distance covered under acceleration of 2.3 m/s²
s = ut + 1/2 at²
= 0 + .5 x 2.3 x 20²
= 460 m
After that it moves under free fall ie g acts on it downwards .
v² = u² - 2gh , h is height moved by it under free fall
0 = 46² - 2 x 9.8 h
h = 107.96 m
Total height attained
= 460 + 107.96
= 567.96 m
b ) At its highest point ,it stops so its velocity = 0
c ) rocket's acceleration at its highest point = g = 9.8 downwards .
At highest point , it is undergoing free fall so its acceleration = g
Answer:
R = 2Ω
Explanation:
Potential difference (V) = current (I) * Resistance (R)
V = IR
I = 2.0A
V = 10v
R = ?
V = IR
R = V / I
R = 10 / 2
R = 2Ω
The resistance across the wire is 2Ω