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3 years ago

Need help asap pls!!!

Physics

2 answers:

MaRussiya [10]3 years ago

7 0

Answer:

A. B. D. E.

Explanation:

all of those are true for it orbits the earth witch orbits the sun

the moon has no atmosphere for if it did then there would be a higher chance for water and plants on the moon

the moon is less deans than the earth and its gravitational pole is 1.62 m/s^2

and in your text book it says Tides are the daily rise and fall of sea level at any given place. The pull of the Moon’s gravity on Earth is the primary cause of tides and the pull of the Sun’s gravity on Earth is the secondary cause. The Moon has a greater effect because, although it is much smaller than the Sun, it is much closer. The Moon’s pull is about twice that of the Sun’s.

ElenaW [278]3 years ago

3 0

Answer:

a,d,e

Explanation:

all of those are true for it orbits the earth witch orbits the sun

the moon has no atmosphere for if it did then there would be a higher chance for water and plants on the moon

the moon is less deans than the earth and its gravitational pole is 1.62 m/s^2

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A gray kangaroo can bound across a fl at stretch of ground 810 with each j ump can-ying it 10 m from the takeoff point. if the k

ivanzaharov [21]

The formula for maximum distance is
X = (V^2 / g) * sin (2 * theta)
10 = (V^2 / 9.8) * sin (2 * 20)
10 = (V^2 / 9.0) * sin(40)
10 = (V^2 / 9.8) * 0.324
v^2 = (10 / 0.324) * 9.8
V^2 = 302.47
v = 17.39 meters/sec (takeoff speed)

The horizontal speed is = Takeoff Speed * Cos(20) = 17.39 * 0.910 = 16.341 meters / sec

6 0

4 years ago

g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the

MrRa [10]

Answer:

Approximately $-1.58\; \rm rad \cdot s^{-2}$ .

Explanation:

This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.

This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:

$v^2 - u^2 = 2\, a\, x$ ,

where

$v$ is the final velocity of the moving object,
$u$ is the initial velocity of the moving object,
$a$ is the (linear) acceleration of the moving object, and
$x$ is the (linear) displacement of the object while its velocity changed from $u$ to $v$ .

The angular analogue of that equation will be:

$(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ , where

$\omega(\text{final})$ and $\omega(\text{initial})$ are the initial and final angular velocity of the rotating object,
$\alpha$ is the angular acceleration of the moving object, and
$\theta$ is the angular displacement of the object while its angular velocity changed from $\omega(\text{initial})$ to $\omega(\text{final})$ .

For this object:

$\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}$ , whereas
$\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}$ .

The question is asking for an angular acceleration with the unit $\rm rad \cdot s^{-1}$ . However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:

$\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}$ .

Rearrange the equation $(\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta$ and solve for $\alpha$ :

$\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}$ .

7 0

3 years ago

(a) A 2.00-µF capacitor is connected to a 18.0-V battery. How much energy is stored in the capacitor?

marshall27 [118]

<h2>Answer:</h2>

1.8 x 10⁻⁵J

<h2>Explanation:</h2>

The energy (E) stored in a capacitor of capacitance, C, when a voltage, V, is supplied is given by;

E = $\frac{1}{2}$ x C x V² -------------------(i)

Now, from the question;

C = 2.00μF = 2.00 x 10⁻⁶F

V = 18.0V

Substitute these values into equation (i) as follows;

E = $\frac{1}{2}$ x 2.00 x 10⁻⁶ x 18.0

E = 1.8 x 10⁻⁵J

Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J

8 0

4 years ago

Read 2 more answers

What is the momentum of a vehicle that has a mass of 1500kg and a velocity of 15m/s? (don't forget the unit is kg*m/s, and needs

alex41 [277]

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 1500 × 15

We have the final answer as

Hope this helps you

4 0

3 years ago

Estefan has determined his BMI at 31. Explain how he can apply the FITT training principles to improve his body composition.

-BARSIC- [3]

Frequency:

Cardio : Five or more
HIIT: 5 or 4

Strength: 2-3 days on non-consecutive days a week

Intensity:
How hard you work during the session

For cardio : workout at your target heart rate.
For HIIT: varying intensity from high to low or rest ( no slow pace)
For strength: you should lift enough weight to complete the needed number of reps and sets.

Time:

For cardio 30- 60 min
For HIIT 45 min (short periods of bursts followed by rest)

For strength depends on the amount of weight.

Type:

Either cardio, HIIT or strength training (resistance training)

NOTE: This info is given by an unqualified brofessor, who uses his hard gained bro-science in the expense of scientific facts to solve others broblems.

7 0

4 years ago