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3 years ago

What forces affect a toy car as it moves down a ramp?

Physics

2 answers:

Hitman42 [59]3 years ago

5 0

I believe friction and gravity work here if i assume that’s the unit you’re working on right now

Amanda [17]3 years ago

3 0

Answer:

gravity

Explanation:

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Suppose a scientist made this model.what info did the scientist need to know in order to make the model

Airida [17]

Suppose I wanted to answer this question about the model.
What info about the model would I need to know in order to
make any intelligent guess about the model ?

Hint:
It would really help if I could SEE the model, or at least a photo of it.

4 0

4 years ago

A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa

vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo = (16.1*25- 160) ft / 5s = 48.5 ft/s

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0

4 years ago

5) Find the length of guitar string that would vibrate at a fundamental frequency of 825 Hz if the string is stretched so that t

Mariulka [41]

Áp dụng công thức tính độ dài ạ

6 0

2 years ago

True or False: An example of an Isometric movement is a plank. please help 2 mins left!<br> PE

Anon25 [30]

Answer:

Yes

Explanation:

The plank (also called a front hold, hover, or abdominal bridge) is an isometric core strength exercise that involves maintaining a position similar to a push-up for the maximum possible time

5 0

3 years ago

Read 2 more answers

Marybeth and Grant are pushing on a wagon, both pushing in opposite directions. Marybeth is pushing to the left with a force of

Vladimir [108]

Answer:

14 N to the right

Explanation:

The net force is equal to the resultant of the forces acting on the wagon. In this case, we are considering two forces acting on the wagon:

- The force applied by Marybeth, to the left, of magnitude 34 N

- The force applied by Grant, to the right, of magnitude 48 N

Since the two forces are in opposite directions, in order to find the net force, we must choose a positive direction. Let's take "right" as positive direction, so the net force is:

$F=+48 N-34 N=+14 N$

And the positive sign means the net force is to the right. Due to this net force different from zero, the wagon will have an acceleration to the right, so if the wagon was at rest, it will start moving to the right.

4 0

3 years ago