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Dafna11 [192]
3 years ago
9

Which statement regarding the diagram is true?

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0

Find out the statement true regarding the diagram given in the question

Answer

the statement is true regarding the diagram is

m∠WXY + m∠YXZ = 180°

REASON

As shown in the diagram

∠WXY and ∠ YXZ  are supplementary angles.

Supplementary angle definition

 Two Angles are said to be Supplementary when there sum is equal to 180 °.

thus  we get

m∠WXY + m ∠YXZ = 180 °

Therefore the m∠WXY + m∠YXZ = 180° is the true statement.


 







 

Semenov [28]3 years ago
4 0
The third option is correct. Those two angles are supplementary and add up to 180 degrees.
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nadya68 [22]

Answers:

4;  20;  3x² - 4x + 3; 52;  17

Step-by-step explanation:

f(-1):  replace x in f(x) = x² + 3 with -1:  f(-1)  =  (-1)² + 3 = 4

f(-4) + g(-1) = (-4)² + 3 + <em>2(-1) + 3</em>  =  16 + 3 <em>- 2 + 3</em> = 20   <em>(since g(x) = 2X + 3)</em>

<em />

3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6  =  3x² - 4x + 3

f(g(2)):  First, evaluate g(2).  It is g(2) = 2(2) + 3 = 7.  Next, use this output, 7, as the input to f(x):    f(g(x)) = (7)² + 3 = 49 + 3 = 52

g(f(2)):  First, evaluate f(x) at x = 2:  f(2) = (2)² + 3 = 7.  Next, use this 7 as the input to g(x):     g(f(2)) = g(7) = 2(7) + 3 = 17

8 0
3 years ago
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If XY= 30, and XZ= 100, then YZ= ____.
marishachu [46]

Answer:

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3 years ago
Orthogonally diagonalize the​ matrix, giving an orthogonal matrix P and a diagonal matrix D. To save​ time, the eigenvalues are
alexgriva [62]

Answer:

P=\left(\begin{array}{ccc}-\frac{2}{3}&-\frac{2}{3}&\frac{1}{3}\\\frac{1}{\sqrt{5}}&0&\frac{2}{\sqrt{5}}\\-\frac{4}{3\sqrt{5}}&\frac{\sqrt{5}}{3}&\frac{2}{3\sqrt{5}}\end{array}\right)

Step-by-step explanation:

It is a result that a matrix A is orthogonally diagonalizable if and only if A is a symmetric matrix.  According with the data you provided the matrix should be

A=\left(\begin{array}{ccc}-9&-4&2\\ -4&-9&2\\2&2&-6\\\end{array}\right)

We know that its eigenvalues are \lambda_{1}=-14, \lambda_{2}=-5, where \lambda_{2}=-5 has multiplicity two.

So if we calculate the corresponding eigenspaces for each eigenvalue we have

E_{\lambda_{1}=-14}=\langle(-2,-2,1)\rangle,E_{\lambda_{2}=-5}=\langle(1,0,2),(-1,1,0)\rangle..

With this in mind we can form the matrices P, D that diagonalizes the matrix A so.

P=\left(\begin{array}{ccc}-2&-2&1\\1&0&2\\-1&1&0\\\end{array}\right)

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D=\left(\begin{array}{ccc}-14&0&0\\0&-5&0\\0&0&-5\\\end{array}\right)

Observe that the rows of P are the eigenvectors corresponding to the eigen values.

Now you only need to normalize each row of P dividing by its norm, as a row vector.

The matrix you have to obtain is the matrix shown below

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