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2 years ago

How to solve 3x-y=11, x+2y=6 with the method of elimination?

Mathematics

1 answer:

zubka84 [21]2 years ago

4 0

Answer:

First point we take the centre number

2[ 3x-y=11]

-1[ x+2y=6]

second we multiply and we adding

6x-2y=22

-x+-2y=-6

_________

5x/5=18/5

x= 3.4

Step-by-step explanation:

third point we take 3x-y=11 any x where we see we change 3.4

3(3.4)-y=11

10.2-y=11

y=10.2-11

y=0.8

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The graph shows a function f(x). Determine the following values.

wel

Answer:

f^-1(4) = 2

f^-1(-5) = -4

f^-1(0) = 0

Step-by-step explanation:

To find the inverse of the function, we simply switch the places of x and y

You simply find the value given on the y-axis and trace to the x-axis

Thus, we have the following ;

f^-1(4) = 2

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3 years ago

The total cost for 8 bracelets including shipping was$54.The shipping charge was$6.Define the variable and write an equation tha

GalinKa [24]

First, we must take away the shipping charge.

x = cost of each bracelet

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Each bracelet is $6. Hope this helps!

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3 years ago

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Anton [14]

x^2-4y^2=16

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.

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4 years ago

Solve like this pls ————>

Westkost [7]

Answer:

7 - 3 = 4

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9 + 11 = 20

7 - (-4) = 28

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3 years ago

A)none B)7 C)6i D)I-6 E) - square of 7 ( look at the picture better)

Anika [276]

The correct answer is A). None

Step-by-step explanation:

The given quadratic polynomial has 3 roots and some of roots are x= $\sqrt{7}$ and x=6+i

It is necessary to note that one of the roots is a complex number and root of complex number always in pair of the conjugate to each other.

Since x=6+i

Conjugate of (6+i) is (6-i)

Therefore, (6-i) is 3rd required root of a polynomial

The correct answer is A). None

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3 years ago

How to solve 3x-y=11, x+2y=6 with the method of elimination?​

How to solve 3x-y=11, x+2y=6 with the method of elimination?