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Igoryamba
4 years ago
5

ASAP ASAP ASAP other question quickly​

Mathematics
1 answer:
Mashcka [7]4 years ago
6 0

Answer:

10 feet from the house.

Step-by-step explanation:

The Pythagorean theorem consists of a^2 + b^2 = c^2.

In this problem we are given a and c, but not b

24^2 + b^2 = 26^2

576 + b^2 = 676

Subtract a from c, 676 - 576 = 100

The square root of 100 is 10

Therefore, the bottom of the ladder is 10 feet from the base of the house.

Hope this helps! :)

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A ladder 15 feet long leans against a wall and forms an angle of 45º with the ground. How far from the wall is the ladder?
bezimeni [28]
The ladder is the hypotenuse of a 45 45 90 triangle.
The legs of a 45 45 90 triangle = hypotenuse / sqroot (2)

15 / 1.414 = 10.608

(Incidentally it is the "bottom" of the ladder that is 10.608 feet from the wall.  The "top" of the ladder is touching the wall.  LOL)

7 0
3 years ago
Read 2 more answers
If anyone could help NOW I would appreciate it
Sveta_85 [38]
3. 5x+2y=-19
10x-7y=-16
10x+4y=-38
10x-7y=-16
11y=-22
Y=-2
10x+4c-2=-38
X=-3

4. 10x-4y=20
2x+7y=43
10x-4y=20
10x+35y=215
-39y=-195
Y=5
10x-4x5=20
X=4

Hope this helped :)
4 0
3 years ago
What number must you add to complete the square?
NikAS [45]

Whenever you complete a square, you're really taking this:

(x+b)^2=x^2+2bx+b^2 [/tex]

And equating roots. Here, the b is clearly 11 (2b=22 implies b=11), so that means we want 121 as our ending number. That means we should add 121 to both sides to get:

x^2+22x+121=9+121 \implies \\ (x+11)^2=130

3 0
4 years ago
Pls help I made it 50 POINTS PLS HELP MEEE
barxatty [35]

Answer:

no 1 is true

Step-by-step explanation:

no2 also true. thank you

5 0
3 years ago
Read 2 more answers
Miss Johnson drives to work everyday when she left for work one day the automator mileage gauge on her car read 38643.8 when she
Over [174]

Answer:

<em>Distance from her house to her work = 12.4 Miles</em>

Step-by-step explanation:

Given :-

<em>==> Automator mileage gauge read 38643.8 Miles before she left to work.</em>

<em>==> Automator mileage gauge read 38668.6 Miles after she came home from work.</em>

<em>==> She didn't drive anywhere else during the day. home to work & work to      home.</em>

Car driven during the day = 38668.6 - 38643.8

                                           = 24.8 Miles

Let the distance from home to work be X

*It is assumed that Distance from home to work = Distance from work to home

So, Distance from work to home = X

Total distance driven during the day = Distance from home to work + Distance from work to home

Total distance driven during the day = X + X

                                                    24.8 = 2X

                                                    24.8 ÷ 2 = X

                                                    12.4 = X

<u><em>Distance from her house to her work = 12.4 Miles</em></u>

8 0
3 years ago
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