ASAP ASAP ASAP other question quickly
1 answer:
You might be interested in
Answer:
So then our model is given by:
Now using the second condition we know that x = 2009-1938 =71 so then we have this:
We can divide both sides by 0.25 and we got:
And then solving for b we got:
So then our model would be given by:
Step-by-step explanation:
For this case we know that for 1938 the minimum wag was 0.25 per hour and for 2009 the new minimum wag was 7.25 per hour.
We want to find an exponential function like this:
Where y represent the value for the minimum wage and x represent the number of years since 1938.
USing the first condition given we know that for 1938 the value of x = 0 and w ehave:
So then our model is given by:
Now using the second condition we know that x = 2009-1938 =71 so then we have this:
We can divide both sides by 0.25 and we got:
And then solving for b we got:
So then our model would be given by:
Answer:
68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
The lengths of a lawn mower part are approximately normally distributed
Standard deviation =
We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)
Formula :
At x = 3.8
Z=-1
Refer the z table for p value
p value =0.1587
At x =4.2
Z=1
Refer the z table for p value
p value =0.8413
P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826
So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.