The balanced equation for the above reaction is as follows
CaCO₃ + 2HBr ---> CaBr₂ + CO₂ + H₂O
stoichiometry of CaCO₃ to HBr is 1:2
number of moles of CaCO₃ reacted - 5.64 g / 100 g/mol = 0.0564 mol
according to molar ratio
number of HBr moles - 0.0564 mol x 2 = 0.1128 mol
number of HBr moles in 250.0 mL - 0.1128 mol
therefore number of HBr moles in 1000 mL - 0.1128 mol / 250.0 mL x 1000 mL = 0.4512 mol
molarity of HBr - 0.4512 M
I am pretty sure shellac they would use in World War II.
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Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance
The reaction for formation of water vapour is as follows ;
2H2+ O2 —> 2H2O
Water vapour is in the gaseous form, at STP , 1 mol of any gas occupies 22.4 L volume
If 22.4 L occupied by 1 mol
Then amount of moles in 436 L - 1/22.4 x 436= 19.5 mol
Stoichiometry of O2 to H2O is 1:2
Amount of O2 moles reacted to formed H2O is -19.5 mol /2 = 9.75 mol
Answer:
a) ΔGº= -49,9 KJ/mol = - 50 KJ/mol
b) The reaction goes to the right to formation of products
c) ΔG= 84,42 KJ/mol. The direction is to reactive, to the left
Explanation:
a) ΔGº= - RTLnKf
You need to convert Cº to K. 25ºC=298K
Then, ΔGº= - 3,814 J/molK * 298K* Ln(5.6 *10^8)= - 49906 J/mol = -49,9 KJ/mol = - 50 KJ/mol
b) The ΔGº < 0, that means the direct reaction is spontaneous when te reactive and products are in standard state. In other words the reaction goes to the right, to formation of products
c) The general ecuation for chemical reaction is aA + bB → cD + dD. Thus
ΔG=ΔGº + RTLn (([C]^c*[D]^d)/[A]^a*[B]^b)
In this case,
ΔG=ΔGº + RTLn ([Ni(NH3)62+] / [Ni2+]*[NH3]^6 )= 84417 J/mol =84,42 KJ/mol
ΔG >0 means the reaction isn't spontaneous in the direction of the products. Therefore the direction is to reactive, to the left