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Greeley [361]
3 years ago
12

N2(g) + 3H2(g) → 2NH3( What is the rate?

Chemistry
1 answer:
Yuri [45]3 years ago
7 0

Answer:

1:3:1:3

Explanation:

N2+ 3×2H ---->N 2×1 H3×2

2÷2 + 6÷2 -------->>>2÷2 6÷2

1 N+ 3H --------1N ×H3

the ratio is 1;:3:1:3

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A block of wood has a volume of 60 cm^3 and a mass of 240 grams calculate its density.
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Answer:

4 g/cm³

Explanation:

Volume(V) = 60 cm³

mass (m) = 240 gm

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 240 / 60

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3 years ago
Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:
AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

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\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

1)

Mass of  Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

2)

Mass of  Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

3)

Mass of  Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

4)

Mass of  Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu

The average mass of iron to be is 54.76 amu.

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3 years ago
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