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Sati [7]
2 years ago
10

The reduced vapor pressure at high altitudes causes a liquid to boil at a temperature.

Chemistry
2 answers:
USPshnik [31]2 years ago
7 0
<h3>Answer:</h3>

            Lower Temperature

<h3>Explanation:</h3>

                        The boiling point is defined as the temperature at which the vapor pressure of a given liquid becomes equal to the external pressure or atmospheric pressure. Boiling point is mainly effected by following factors:

1) Inter-Molecular Interactions:

                                                     Greater the intermolecular interactions greater will be the boiling point because more energy is required to overcome these intermolecular interactions.

Example:

                                          Water  =  100 °C

                              Diethyl ether  =  34.5 °C

Water requires more energy because it contains hydrogen bond interactions which are considered the strongest intermolecular interactions. While, Diethyl ether lacks Hydrogen bondings.

2) External Pressure:

                                    The boiling point also varies with changing the external pressure for the same solvent. Greater the external pressure greater will be the boiling points and <em>vice versa</em>.

Example:

Water:

                    External Pressure                       Boiling Point

                                1 atm                                         100 °C

                             0.921 atm                                     98 °C

                             0.425 atm                                     72 °C

irinina [24]2 years ago
5 0
<span>At higher altitudes (and thus lower atmospheric pressures), water boils at a lower temperature. This is because the lack of vapor pressure at that altitude doesn't constrain the speed of the molecules with barometric pressure. Therefore, the water begins boiling at a lower temperature. This is often a disadvantage because even if the water is boiling, it won't be hot enough for meals (which is why heat and temperature are distinct). That's why we have pressure cookers, which manage to keep a stable boiling point.
Did that help?</span>
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Explanation:the greater the overlap the greater the strength of the bond.

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Which of the following is a way that some animals bodies adapt to living in extremely cold climates
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Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o
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<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

<u>For 2:</u> The amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

<u>Explanation:</u>

  • <u>For 1:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of KIO_3 solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol

Hence, the amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

  • <u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = \frac{1}{2}\times 0.00025=0.000125mol of sodium thiosulfate

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6 0
3 years ago
A 25.0 g bold made of an alloy absorbed 250 J of heat as its temperature changed from 25.0 °C to 78.0 °C. What is the specific h
nata0808 [166]

Answer:

Specific heat of alloy = 0.2 j/ g.°C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of bold = 25 g

Heat absorbed = 250 J

Initial Temperature = 25°C

Final temperature = 78°C

Specific heat of alloy = ?

Solution:

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ΔT = 78°C - 25°C

ΔT = 53°C

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Q = m.c. ΔT

250 j = 25 g × c ×53°C

250 j = 1325 g.°C × c

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