2. Find the length of segment JK with endpoints J(4,8) and K(-1,-2). Leave answer as a

Mathematics

1 answer:

yuradex [85]3 years ago

3 0

Answer:

Distance of JK = 15 unit

Step-by-step explanation:

Given:

J(4,8)

K(-1,-2)

Find:

Distance of JK

Computation:

Distance = √(x₂-x₁)² + (y₂-y₁)²

Distance of JK = √(-1-4)² + (-2-8)²

Distance of JK = √25 + 100

Distance of JK = √125

Distance of JK = 15 unit

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Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

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$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

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