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2 years ago

7x2 +11x-6/7x2 - 10x + 3

Mathematics

2 answers:

allsm [11]2 years ago

4 0

Answer:

Here's what I get.

Step-by-step explanation:

$\dfrac{ 7x^{2} + 11x - 6}{ 7x^{2} - 10x + 3}$

One way is to factor the numerator and the denominator

$\dfrac{ 7x^{2} + 11x - 6}{ 7x^{2} - 10x + 3} = \dfrac{(7x - 3)(x + 2)}{ (7x - 3)(x - 1)} = \dfrac{x+2}{x-1}\\\\\text{Except when } x = \dfrac{3}{7}$

velikii [3]2 years ago

3 0

Answer:

Final result :

x + 2

—————

x - 1

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 7 • 3 = 21

Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 .

-21 + -1 = -22

-7 + -3 = -10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3

7x2 - 7x - 3x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

7x • (x-1)

Add up the last 2 terms, pulling out common factors :

3 • (x-1)

Step-5 : Add up the four terms of step 4 :

(7x-3) • (x-1)

Which is the desired factorization

Please mark brainliest and have a great day!

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20 points!!!

Svetlanka [38]

The answer is: {4, 1} .
________________________________________________________
Explanation:
________________________________________
Given the equations:
________________________________________
"12x = 54 − 6y ;
"-17x = -62 − 6y ;
_________________________________________
Multiply the second equation (both sides) by "-1" ;
___________________________________________
-1*{-17x = -62 − 6y} ;

to get:

17x = 62 + 6y ;
___________________________________________
{Note: The reason we do this is that we notice the TWO "-6y" values; and by multiplying one of the entire equations by "-1" ; we can change said equation to an equation with a "(+6y)" value; and the "(+6y)" and the "(-6y)" values cancel out to "zero" ; providing an opportunity to isolate "x"; and to solve for "x".}.
___________________________________________
Now, rewrite the two equations:
___________________________________________

12x = 54 − 6y ;
17x = 62 + 6y ;
___________________________________________
↔ Rewrite; and then add the two together:

6y + 62 = 17x
-6y + 54 = 12x
____________________
0 + 116 = 29x ;

↔ 29x = 116 ;

Divide EACH SIDE of the equation by "29" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
________________________________________________
29x / 29 = 116 / 29 ;
________________________________________________
to get:
________________________________________________
x = 4 .
______________________________________________
Now that we have the value for "x" , which is "4" ; let us plug in "4" for "x" for either of the original two equations, to solve for "y". In fact, let us try substituing "4" for "x" ; for BOTH of the two original equations; to see if the value is correct.
_____________________________________________
Our original two given equations are:
_____________________________________________
"12x = 54 − 6y ;

"-17x = -62 − 6y ;
_____________________________________________
Let us start with the first equation:
________________________
" 12x = 54 − 6y " ;
__________________________________
When "x = 4" ; what does "y" equal ?

Plug in "4" for "x" ; to solve for "y" ;

12(4) = 54 − 6y ;

→ 48 = 54 − 6y ;

Subtract "54" from EACH SIDE of the equation;

→ 48 − 54 = 54 − 6y − 54 ;

to get:

→ -6 = -6y ;

→ Divide EACH side of the equation by "-6" ; to isolate "y" on one side of the equation ; and to solve for "y" ;

→ -6/-6 = -6y / -6 ;

to get:

1 = y ; ↔ y = 1 ; So, we have: x = 4, y = 1 ; or, {4, 1}.
______________________________________________
Let us check to see, if the second (orginal equation) holds true when "x = 4" and "y = 1 " ;
______________________________________________
The second "original equation" given is:
______________________________________________
" -17x = -62 − 6y " ;
______________________________________________
→ -17(4) = ? -62 − 6(1) ?

→ -68 = ? -62 − 6 ?

→ -68 = ? -68 ? Yes!
________________________________________________________
The answer is: {4, 1} .
________________________________________________________

4 0

2 years ago

A skilled chess player believes that when they play a novice opponent, there is a 90% probability they will be able to beat them

zavuch27 [327]

Answer:

b) Binomial

c) Poisson

Step-by-step explanation:

The geometric distribution is the number of trials required to have r successes. The measures the number of sucesses(wins), not the number of trials required to win r games. So the geometric distribution does not apply.

For each match, there are only two possible outcomes, either the skilled player wins, or he does not. The probability of the skilled player winning a game is independent of other games. So the binomial distribution applies.

We can also find the expected number of wins of the skilled player, which is 15*0.9 = 13.5. The Poisson distribution is a discrete distribution in which the only parameter is the expected number of sucesses. So the Poisson distribution applies.

So the correct answer is:

b) Binomial

c) Poisson

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