Question

Find the value of x, rounded to the nearest tenth​

Answer 1

Answer:

x ≈ 8.9

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, the the square of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 8(8 + 2) = 8 × 10 = 80 ( take the square root of both sides )

x = $\sqrt{80}$ ≈ 8.9 ( to the nearest tenth )