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Simora [160]
3 years ago
8

Find the value of x, rounded to the nearest tenth​

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0

Answer:

x ≈ 8.9

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, the the square of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 8(8 + 2) = 8 × 10 = 80 ( take the square root of both sides )

x = \sqrt{80} ≈ 8.9 ( to the nearest tenth )

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A) The mean would be 1.842 and the standard deviation would be 1.339.
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Explanation
a) This can be modeled as a binomial distribution, since there are two outcomes (7 or not 7), the events are independent (getting a 7 on one spin does not influence the chance of a 7 on the next spin) and there are a fixed number of trials (70).  In a binomial distribution, the mean is given by n*p, where n is the number of trials and p is the probability.

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b) To determine if this is unusually low, we find the probability:
_nC_k\times p^n\times (1-p)^{k-n}
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