Find the value of x, rounded to the nearest tenth
1 answer:
Answer:
x ≈ 8.9
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, the the square of the tangent is equal to the product of the external part of the secant and the entire secant, that is
x² = 8(8 + 2) = 8 × 10 = 80 ( take the square root of both sides )
x = ≈ 8.9 ( to the nearest tenth )
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Answer:
<h2>√34sin(x + 0.33π)</h2>Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²
Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34
in radians;
3 cos x + 5 sin x = √34sin(x + 0.33π)