Answer:
It is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg because the probability of this event is large enough.
Step-by-step explanation:
Population mean=μ=3.3.
S.E=0.1.
n=36.
If the probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is larger than the it will be likely. The probability can be calculated by normal distribution because sample size is large enough.
Z-score for 3.2 kg=3.2-3.3/0.1=-1
Z-score for 3.4 kg=3.4-3.3/0.1=1
P(-1<Z<1)=P(-1<Z<0)+P(0<Z<1)
P(-1<Z<1)=0.3413+0.3413
P(-1<Z<1)=0.6826
The probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is 68.26%. So. it is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg as the probability is large enough.
Answer:
Option(b)
The range of numbers that satisfy the inequality x greater that 12.4 is the range of numbers has a lower limit but no upper limit Option(b)
E<u>xplanation: </u>
The range of numbers are described in a condition X> 12.4
here the value 12.4 is said to set as the threshold value
(i.e) the lower most value taken into account. The greater than symbol indicates that inequality value should be greater than 12.4. Therefore it is summarized that the lower limit is limited to 12.4 value and the upper value has no limit.
Answer:
First, you add 11 to the other side of the equals sign. So it would be 2x=k+11. Now, you divide 2 from x and do the same on the other side of the equals sign. so x= k+11
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2
Step-by-step explanation:
The probability of loss is
1 - 0.2 - 0.1 = 0.7
Answer:
ninety-eight dollars and three cents
Step-by-step explanation: