The inequality for sec (x) < cot (x) is; π/2 < x < π
<h3>How to express trigonometric inequality?</h3>
We are given that;
We want to find the intervals that the trigonometric inequality sec (x) < cot (x) always hold true.
This can also be expressed as;
1/cos (x) < 1/tan (x)
Now, this can happen only in the quadrant where tan (x) is negative and cos x is positive which is in fourth quadrant where;
π/2 < x < π
The inequality for sec (x) < cot (x) is; π/2 < x < π
Read more about Trigonometric Inequality at; brainly.com/question/12094532
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I only know the answer to number 4 and I believe that it is C
It’s the letter c
40>36=4% 94%-4%=90
Answer:
the event is odds against an event of the 19 to 12 is probability is the 19
I don't understand your choices but it would be p is greater than or equal to $140*11 if p=pay