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Aleonysh [2.5K]
3 years ago
15

Use the following scenario and data for all questions During lunch time, customers arrive at a postal office at a rate of per ho

ur. The interarrival time of the arrival process can be approximated with an exponential distribution. Customers can be served by the postal office at a rate of per hour. The service time for the customers can also be approximated with an exponential distribution. For each of the following questions, show your work and use the right notation. Determine the utilization factor.
A) rho =4/5
B) rho =5/4
C) rho =2/3
D) rho=45-36=9
E) None of the above.
Determine the probability that the system is idle, i.e., no customer is waiting or being served.
A) rho_0= 4/5
B) rho_0= 5/4
C) rho_0=1/5
D) rho_0= 1/9
E) None of the above
Determine the probability that exactly one customer is in the system, i.e., no customer is waiting but one is served.
A) rho_1=1/9
B) rho_1=2/5
C) rho_1=1/5
D) rho_1=4/25
E) None of the above
Determine the probability that exactly one customer is waiting
A) p_2=2/81
B) p_2=16/125
C) p_2=4/125
D) p_2=4/25
E) None of the above
Determine the expected number of customers in the system including the one being served and the ones waiting in the queue
A) L=4
B) L=16/5
C) L=12/5
D) L=18/5
E) None of the above
Determine the expected length of the queue, i.e., the number of customer waiting in the queue.
A) L_q=4
B) L_q=16/5
C) L_q=12/5
D) L_q=18/5
E) None of the above

Business
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

Check the explanation

Explanation:

The assumptions in single-server queue theory include: -

  1.    Unlimited calling population may enter the queue
  2.    Arrivals occur randomly and are not dependent but average number of arrival does not change.
  3.    Single waiting line and arriving customers are patient customers who can wait in the queue before they can be served regardless of the length of the line.
  4.    Arrivals are serviced on a first come first served basis
  5.    Service time of one customer may vary from that of another customer.

Kindly check the attached images below to see the step by step explanation to the question above

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The following data was collected from the manufacturing of an auto component. It represents the diameter (in mm) of that compone
andre [41]

Answer:

9.37

Explanation:

The computation of LCL for a control chart is shown below:-

Sample  Obs 1  Obs 2    Obs 3   Obs 4   Mean observation    Range

1                 10      12           12          14              12                         4

2                 12     11            13          16              13                          5

3                 11      13            14           14              13                          3

4                 11       10            7            8               9                          4

5                13     12             14            13             13                         2

For computing the mean observation  and range we will use the below formulas

Mean observation = ( Obs 1 + Obs 2 + Obs 3 + Obs 4) ÷ 4

Range = Highest value - Lowest value

LCL =  \bar{\bar{X}} - A2 \bar{R}

\bar X =  ( 12 + 13 + 13 + 9 + 13 ) ÷ 5

= 12

\bar R =  ( 4 + 5 + 3 + 4 + 2 ) ÷ 5

= 3.6

Since we found the value of A2 with the help of constants table for control charts for a 4 subgroup size.

A2  = 0.729

LCL =  \bar{\bar{X}} - A2 \bar{R}

12 - 0.729 × 3.6

= 9.37

5 0
3 years ago
On July 28, Vent Corp. sold $500,000 of 4%, eight-year subordinated debentures for $450,000. The pur­chasers were issued 2,000 d
KengaRu [80]

Answer: Vent should record $70,000

Explanation:

The requirement is to determine the amount of discount on the debentures that Vent should record at issuance.

ASC Topic 470 states that the proceeds from the issuance of debt with detachable stock warrants should be allocated between the bonds and the warrants based upon their relative fair values at the time of issuance.

In this case, the fair value of the bonds is not known, but the fair value of the warrants is $10 per warrant. Thus, the total fair value of the warrants is $20,000 ($10 × 2,000 warrants). The fair value of the debentures can be estimated to be $430,000 ($450,000 total proceeds – $20,000 fair value of warrants). The face value of the bonds $500,000 less the fair value of the bonds of $430,000 equals the bond discount of $70,000.

6 0
3 years ago
Arntson, Inc., manufactures and sells two products: Product R3 and Product N0. The annual production and sales of Product of R3
Tcecarenko [31]

Answer:

$695.24 per unit

Explanation:

Calculation to determine what The unit product cost of Product R3 under activity-based costing is closest to

First step is to Calculate Activity rates

Activity Cost Pool Activity driver Overhead Cost (A) Expected Activity (B) Activity rate (A/B)

Labor related Number of DLH $ 40,636÷13,000 = 3.13 Per DLH

Production orders Number of Order 65,880÷ 1,600= 41.18 Per Order

Order size Number of MH 433,075÷ 7,600 = 56.98 Per MH

Second step is to calculate the Cost assigned to Product R3

Cost assigned to Product R3

Activity name Activity Rates Activity ABC Cost

(A) (B) (A x B)

Labor related 3.13 * 11,000 =$34,430

Production orders 41.18* 1,200=$49,416

Order size 56.98*3,900= $222,222

Total Overheads assigned $306,068

($34,430+$49,416+$222,222)

Production 1,100

Overhead cost per unit $278.24

Product R3

Direct material $211

Direct labor (10x $20.60 per DLH) $206

Overheads $278.24

Total Cost per unit $695.24

($211+$206+$278.24)

Therefore The unit product cost of Product R3 under activity-based costing is closest to $695.24 per unit

3 0
2 years ago
Suppose you held a diversified portfolio consisting of a $7,500 investment in each of 20 different common stocks. The portfolio'
MA_775_DIABLO [31]

Answer:

The new portfolio beta is 1.31 rounded off to two decimal places.

Explanation:

The portfolio beta is a function of the sum of the weighted average betas of the individual stock's that form up the portfolio. The portfolio beta is calculated using the following formula,

Portfolio beta = wA * Beta of A + wB * Beta of B + ... + wN * Beta of N

Where,

  • w is the weightage of each stock in the portfolio

The beta of the portfolio when one stock with a beta of 1 is sold is,

The sum of individual stock betas for 19 stocks is = 20 * 1.31  -  1 * 1  = 25.2

The new portfolio beta when one stock with a beta of 0.97 is added is,

Portfolio beta = (25.2 + 0.97) / 20

Portfolio beta = 1.3085 rounded off to 1.31

4 0
3 years ago
In preparing a statement of cash flows under the indirect method, a decrease in accounts receivable would be reported as a(n): M
denpristay [2]

Answer:Addition to net income in the operating activities section

Explanation:

8 0
2 years ago
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