That would be true so you make sure you have all the correct info to put on the application
Answer:
Present value deposit today = 216,886 (Approx)
Explanation:
Given:
Number of year (n) = 16 years x 4 quarter = 64
Rate of interest (r) = 1.6% = 0.016 / 4 = 0.004
Future value = $280,000
Present value = ?
Computation of present value deposit today:

Present value deposit today = 216,886 (Approx)
Based on the information given for Server Company, the machine will be valued a<u>t $42,000 </u>and the machinery account will be credited.
<h3>What would be the value of the machine?</h3>
The machine was sold on January 1, 20X9 and at that point, the accumulated depreciation was $28,000.
The value of the machine was therefore:
= Cost of machine - Accumulated depreciation
= 70,000 - 28,000
= $42,000
Find out more on accumulated depreciation at brainly.com/question/1287985.
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Answer:
False
Explanation:
The interview process may or may not end depending on the type of interview conducted by the organization.
If it is on-spot offer: On-spot offer, interview the candidates and provide a spot offer and even do verification on the same day.
If it is walk-in: It depends on the process that the organization has planned each time. Mostly there will be multiple rounds, each will be conducted in one day depending on the strength of the candidate.
Job fairs: It is possible only to conduct the initial round. So it does not end in one day.
Answer:
![A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%20%281.12%29%5E4%7D%7B%281.12%29%5E4%20-1%7D%5D)
![A = 28000 [\frac{0.12*1.574}{1.574-1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%2A1.574%7D%7B1.574-1%7D%5D)

So then the annual pay would be $ 9218.564 for this case
Explanation:
For this question we can use the Equivalent annual value (A) given by the following expression:
![A = PV [\frac{i (1+i)^t}{(1+i)^t -1}]](https://tex.z-dn.net/?f=%20A%20%3D%20PV%20%5B%5Cfrac%7Bi%20%281%2Bi%29%5Et%7D%7B%281%2Bi%29%5Et%20-1%7D%5D)
Where
represent the pesent value
since the rate is yearly
since we have 4 years to pay
So then we have everything to replace and we got:
![A = 28000 [\frac{0.12 (1.12)^4}{(1.12)^4 -1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%20%281.12%29%5E4%7D%7B%281.12%29%5E4%20-1%7D%5D)
![A = 28000 [\frac{0.12*1.574}{1.574-1}]](https://tex.z-dn.net/?f=%20A%20%3D%2028000%20%5B%5Cfrac%7B0.12%2A1.574%7D%7B1.574-1%7D%5D)

So then the annual pay would be $ 9218.564 for this case
And this amount would be paid each year in order to pay all the money after 4 years.