1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovikov84 [41]
3 years ago
5

How do you solve this?

Mathematics
1 answer:
andrew-mc [135]3 years ago
7 0
<span>Are you from Connections Academy, public school or any other online school? Then join our discord, we help each other out with homework and just chill. discord. gg/ qZcMArh (make sure to remove the spaces) WE also have our own tutors that can help you! (if the discord link didn't work add ugly guy#1805 on discord. ( we're also a active group that requires a verified email to join due to trolls. It's not hard to do thankfully just go to discord app and sign up : ) |) Connections Academy Discord Online School Discord Homework Help Discord Connexus Discord Public School Discord Connections Discord Academy Discord Connections Academy Reddit Connexus Reddit Connexus Connections Academy Instagram Connections Academy Twitter Connexus homeschool discord homeschool reddit connections academy twitter connections academy discord</span>
You might be interested in
Find the common difference of the arithmetic sequence -14, -5, 4, ...
torisob [31]
The correct answer is 9
3 0
3 years ago
2<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B5%7D%2B4%5C%5C" id="TexFormula1" title="\sqrt{x+5}+4\\" alt="\sqrt{x+5}+4\\" al
Andreyy89

2 \sqrt{x + 9}

8 0
2 years ago
Read 2 more answers
Hiii would you like to be my friend? if you don't want to then I understand ^-^
mr Goodwill [35]

Answer:

hiii sure!!

Step-by-step explanation

5 0
3 years ago
Read 2 more answers
Solve for b.<br> 15 - 3b=63
kirill115 [55]
15-3b=63
subtract 15 from both sides
-3b=48
divide -3 from both sides
b= -16
5 0
3 years ago
Read 2 more answers
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
Other questions:
  • Find a recursive rule for the sequence 2 4 6 10
    6·1 answer
  • Choose one. Statistics are A) Measures of populations; B) Always estimations; C) Notated with small Roman letters; D) (b) and (c
    12·1 answer
  • The product of 3/4 and a number s is 3/5
    7·1 answer
  • Please, help me on this question, guys! I know the answer for (a) so I'll write down, too. For (b) I tried "$89,000 because that
    6·1 answer
  • Mrs berry was riding a bicycle on a path. After riding 2/3 of a mile , she discovered that she still needed to travel 3/4 of a m
    9·1 answer
  • What is -9 to the second power
    6·2 answers
  • Anyone can help me solve this question3a^2b^2-17abxy+10x^y^2 using the Cross multiplication method!?
    11·1 answer
  • Dalinda spins a spinner 60 times the table shows her data
    15·1 answer
  • When using "mean" does it mean average of something if not please explain, I'm a bit confused.
    7·2 answers
  • Geometry help greatly needed, check photo for more information! &lt;3
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!