Order the fractions from least, to greatest, 3 6 4 5 5 12

9

Mnenie [13.5K]

Answer: n = 75; p = 30

Explanation: (a) 5p + 4n = 450 where p is for pen and n is for notebook.

(b) 10p + 3n = 525

We can use the elimination method to solve these two equations.

1. Multiply the first equation by 2 so that 10p will cancel out:

2(5p + 4n = 450)

- 10p + 3p = 525

10p + 8n = 900

- 10 p + 3n = 525

5n = 375

2. Divide by 5 to get n alone: n = 75

3. Plug 75 into the first equation: 5p + 4(75) = 450

5p + 300 = 450

4. Subtract 300 from 450: 5p = 150

5. Divide by 5 to get p alone: p = 30

We can test if this is correct by plugging our answers into the second equation:

10(30) + 3(75) = 525

300 + 225 = 525

525 = 525

This is a true statement, which means that our answers are correct.

6 0

3 years ago

I WILL GIVE YOU BRAINLESEST IF YOU GET IT CORRECTT PLEASEEEEE

never [62]

Answer:

a. 7/8

Because 7/8 is 7 divided by 8

Plz mark brainliest

7 0

2 years ago

Read 2 more answers

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

6 0

3 years ago

How many different arrangements of the letters in the word SCHOOL are there?

pogonyaev

36; there are 6 letters in the word school so if you multiple it by 6 which is the amount of different places one letter could be, the result would be 36

4 0

3 years ago

Read 2 more answers

The volume of the figure. Round to the nearest tenth

Mama L [17]

The answeris675 yards

3 0

3 years ago

Order the fractions from least, to greatest, 3 6 4 5 5 12​

Order the fractions from least, to greatest, 3 6 4 5 5 12