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pickupchik [31]
3 years ago
5

Lucia compro 12 pares de media a 60 pesos cada una 7 remeras a 156 pesos cada una y 2 pantalones a 350 pesos cada uno.Si pago co

n 3000 pesos¿le sobro o le falto dinero?¿cuanto?
Mathematics
1 answer:
earnstyle [38]3 years ago
5 0

Answer:

A Lucia le sobró dinero y la cantidad que sobró es: 488 pesos.

Step-by-step explanation:

Para determinar si le faltó o le sobro dinero, debes determinar el costo total de lo que compró multiplicando el precio de cada artículo por la cantidad comprada y sumando estos valores:

(60*12)+(156*7)+(350*2)=720+1092+700=2512

Dado que pagó con 3000 pesos y el costo total de lo que compró es de 2512 pesos y este valor es menor que 3000 en 488 pesos, la respuesta es que le sobró dinero.

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The product of two consecutive negative even integers is equal to 30 more than the first. Find the integers. write the solutiojs
nlexa [21]

Answer:

The numbers are -6 and -4.

Step-by-step explanation:

x * (x + 2) = x + 30\\x^{2} + 2x = x + 30\\x^{2} +x-30=0\\(x+6)(x-5)=0\\

x = -6 and x = 5 (which is not negative).

5 0
3 years ago
What’s the answer please and thank you!
vfiekz [6]

Answer:

Subtraction Property on Equality.

Step-by-step explanation:

2. 15x + 6 = -24

15x + 6 - 6 =  -24-6

15x = -30

Subtraction Property on Equality.

5 0
4 years ago
Rewrite the expression in the form 9^n<br> (9^3) (9^12)
BartSMP [9]

Answer:

{9}^{15}

Step-by-step explanation:

( {9}^{3} ) \times ( {9}^{12} ) = 9 {}^{3 + 12}  =  {9}^{15}  \\

5 0
3 years ago
Find the indicated limit, if it exists.
jok3333 [9.3K]
For the limit to exist, the limits from either side must also exist and be identical. We have

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1

Since the limits do not match, the overall limit does not exist.
6 0
3 years ago
 A Finance professor created a multiple-choice examination with 100 questions for his students. Each question has five possible
seropon [69]

Answer:

a. 0.011 or 1.1%

b. 31.56% or 0.3156

c. 99.94% or 0.9994

d. 3.42% or 0.0342

Step-by-step explanation:

Given

Number of multiple choice questions = 100

Probability of success for students who have attended lectures and done their homework = 0.85

a. Using binomial distribution

Probability of correctly answering 90 or more questions out of 100

= \sum^{100}_{x=90}\left {100} \atop {x}} \right C (0.85)^x(0.15)^{100-x}\\=0.011

Since,

In Binomial Distribution

P(X=x) =\left {h} \atop {x}} \right.C  P^x q^{n-x}

where x=0,1,...,n

and q=1-P

Probability is therefore 1.1% or 0.011

b. Probability of correctly answering 77 to 83 questions out of 100

= \sum^{83}_{x=77}\left {100} \atop {x}} \right C (0.85)^x(0.15)^{100-x}\\=0.3156

The probability is therefore 31.56% or 0.3156

c. Probability of correctly answering more than 73 questions out of 100

= \sum^{100}_{x=73}\left {100} \atop {73}} \right C (0.85)^x(0.15)^{100-x}\\=0.9994

The probability is therefore 99.94% or 0.9994

d. Assuming that the student has answered randomly

Probability of success = 1/5 = 0.2

Probability of failure = 1 - 0.2 = 0.8

Probability of answering 28 or more questions correctly

= \sum^{100}_{x=28}\left {100} \atop {x}} \right.c  (0.2)^x(0.8)^{100-x}\\=0.0342

The probability is therefore 3.42%

5 0
3 years ago
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