Ouuuuuuuuuu I want a cookie
Are you asking to find the area
Answer:
Second well was
deep below the surface.
Step-by-step explanation:
Given:
Depth of First well = ![46\frac{2}{3}\ m](https://tex.z-dn.net/?f=46%5Cfrac%7B2%7D%7B3%7D%5C%20m)
can be Rewritten as ![\frac{140}{3}\ m](https://tex.z-dn.net/?f=%5Cfrac%7B140%7D%7B3%7D%5C%20m)
Depth of First well = ![\frac{140}{3}\ m](https://tex.z-dn.net/?f=%5Cfrac%7B140%7D%7B3%7D%5C%20m)
Also Given:
The second well had more water, and was
deeper than the first well.
can be Rewritten as ![\frac{467}{6}\ m](https://tex.z-dn.net/?f=%5Cfrac%7B467%7D%7B6%7D%5C%20m)
Hence We can say that;
Depth of second well is equal to
plus Depth of First well.
framing in equation form we get;
Depth of second well = ![\frac{467}{6}+\frac{77}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B467%7D%7B6%7D%2B%5Cfrac%7B77%7D%7B3%7D)
Now the denominators are common so we can solve the numerators
now to solve the fractions we need to make the denominator common we will use L.C.M we get;
Depth of second well = ![\frac{467\times1}{6\times1}+\frac{77\times2}{3\times2}= \frac{467}{6}+\frac{154}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B467%5Ctimes1%7D%7B6%5Ctimes1%7D%2B%5Cfrac%7B77%5Ctimes2%7D%7B3%5Ctimes2%7D%3D%20%5Cfrac%7B467%7D%7B6%7D%2B%5Cfrac%7B154%7D%7B6%7D)
Now the denominators are common so we can solve the numerators.
Depth of second well = ![\frac{467+154}{6}=\frac{621}{6}\ m \ \ OR\ \ 103 \frac{3}{6}\ m](https://tex.z-dn.net/?f=%5Cfrac%7B467%2B154%7D%7B6%7D%3D%5Cfrac%7B621%7D%7B6%7D%5C%20m%20%5C%20%5C%20%20OR%5C%20%5C%20103%20%5Cfrac%7B3%7D%7B6%7D%5C%20m)
Hence Second well was
deep below the surface.
A (it’s a slight increase)
if you have a TI-84 calculator you could solve this problem in seconds.
Answer:
B.)The new pyramid has a volume that is One-half the volume of the original pyramid.
Step-by-step explanation:
got it right on test.