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pochemuha
3 years ago
10

The proof ABC ≅ DCB that is shown.

Mathematics
2 answers:
miskamm [114]3 years ago
8 0

Solution:

Given: ∠A≅∠D and CD║AB

To Prove: Δ ABC ≅  ΔD CB

Proof:

1. ∠A=∠D→→(Given)

2. As, CD ║AB, ⇒ ∠DCB=∠ABC→→(when lines are parallel, Alternate interior angles are equal.)

3. Segment CB=Segment BC→→Reflection property

⇒Δ ABC ≅  ΔD CB →→(Angle Angle Side or AAS)

Schach [20]3 years ago
4 0

The <em><u>correct answer</u></em> is:

AAS

Explanation:

AAS stands for "angle-angle-side."  This states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of another triangle, then the triangles are congruent.

In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with.  Throughout the proof, we find that ∠ABC ≅ ∠DCB.  We also have that CB is congruent to itself.  This is two angles and a side not included, so this is AAS.

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Identify the outliers of the data set. Then determine if the outlier increases or decreases the value of the mean.
Juli2301 [7.4K]
<h3>Answer:  D) 76; increases</h3>

========================================================

Explanation:

The main group or cluster of values spans from 32 to 42 (inclusive).

Then off on its own is the value 76, which we consider an outlier. This value is fairly far from the group. As a rule, large outliers pull on the arithmetic mean to make it larger than it should be. Think of it like the outlier pulling on the mean as if it was done through a magnet or gravitational pull.

Similarly, small outliers pull the mean to the left to make it smaller than it should be. We don't have any small outliers in this case.

--------------

Let's consider the set

A = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 46}

where I've sorted the values and I replaced 76 with 46.

Computing the mean of set A gets us

(32+34+35+36+37+38+38+41+42+42+46)/11 = 38.27 approximately

--------------

Now let's form this set

B = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 76}

which is the original set your teacher gave you. It's nearly identical to set A, except that the 46 is now 76 again.

Compute the mean of set B

(32+34+35+36+37+38+38+41+42+42+76)/11 = 41

---------------

Set A has a mean of roughly 38.72 and set B has a mean of 41. We see that the mean has increased.

3 0
3 years ago
A proportional relationship is represented by the equation 2x = 18y. IF y = kx, where k is the constant of proportionality, find
ddd [48]
2x=18y
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4 years ago
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Step-by-step explanation:

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