Question

PLEASE HELP!!!!! "A country's population in 1991 was 70 million. In 1998 it was 74 million. Estimate the population in 2010 using the exponential growth formula. Round your answer to the nearest million."

Answer 1

Answer:

81 million

Step-by-step explanation:

A = Pe^rt

Let's break this equation down.

A is the total you will have.

P is the starting value.

R is the rate

T is the time.

Let's find the rate first.

74000000 = 70000000e^7r

Divide each side by 70mil

74000000/70000000 = e^7r

Then take the ln() of each side.

ln(74000000/70000000) = 7r

0.0556 = 7r

r = 0.0079

Now we can find how many people will be there in 2010.

A = 70,000,000e^(19 * 0.0079)

A = 81336530.2373

Now we round to the nearest million, leaving us with 81 million.