3 years ago

PLEASE HELP!! 4/3n - 8 = -6

Mathematics

1 answer:

yuradex [85]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is the distance in the standard (x, y) coordinate<br> plane between the points (2,3) and (5,5)?

Naddik [55]

<h3>The distance between the points (2,3) and (5,5) is 3.6 units</h3>

<em><u>Solution:</u></em>

<em><u>Distance between two points is given by:</u></em>

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

We have to find the distance in the standard (x, y) coordinate plane between the points (2,3) and (5,5)

From given,

$(x_1, y_1) = (2, 3)\\\\(x_2, y_2) = (5, 5)$

Substituting the values we get,

$d = \sqrt{(5-2)^2 + (5-3)^2}\\\\Simplify\\\\d = \sqrt{3^2 + 2^2}\\\\d = \sqrt{9+4}\\\\d = \sqrt{13}\\\\In\ decimal\ form\\\\d = 3.605 \approx 3.6$

Thus distance between the points (2,3) and (5,5) is 3.6 units

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3 years ago