All categories

4 years ago

How do you find the total magnification of a microscope?

1 answer:

6 0

In order to find total magnification of a microscope, you need to multiply the power of eyepiece and objective lens.

Hope this helps!

You might be interested in

Example: What power of spectacle lens is needed to correct the vision of a nearsighted person

Aleksandr [31]

<h3>Concave or diverging lens is needed correct the vision of a nearsighted person whose far point is 30.0 cm</h3>

<em><u>Solution:</u></em>

Nearsighted person will not be able to see the distant objects clearly

Now, we want the near sighted person to see the distant objects clearly

<em><u>The lens equation is given as:</u></em>

$P = \frac{1}{d_o} + \frac{1}{d_i}$

For distant vision, $d_0 = \infty$

$d_i = image\ distance\\\\d_0 = lens\ to\ retina\ distance$

The image of 30 cm from eye will be 28.5 cm to left of spectacle lens

Therefore,

$d_i = -28.5\ cm = 0.285\ meter$

From lens equation,

$P = \frac{1}{ \infty } + \frac{1}{-0.285\ meter}\\\\P = 0 - 3.51 \\\\P = -3.51\ diopter$

The negative power -3.51 D denotes that a concave or diverging lens is needed

4 0

3 years ago

Six dogs pull a two-person sled with a total mass of 220 kg. The coefficient of kinetic friction between the sled and the snow i

irina [24]

Answer:

a) 2457J

b) 558W

c) 337N

Explanation:

Assuming dogs started from rest.

$v=a*t\\t=\frac{a}{v}\\v=12\frac{km}{h}\frac{1000m}{km}*\frac{1h}{3600s}\\\\v=3.3m/s\\\\t=\frac{3.3m/s}{0.75m/s^2}\\t=4.4s$

and the displacement is given by:

$d=\frac{1}{2}*a*t^2\\d=7.3m$

Using the energy conservation formula:

$K_i+U_i+W_d+W_f=K_f+U_f$

Because the motion started from rest the initial kinetic energy is zero, the motion occurred in-ground level so the gravitational energy is zero too.

the work done by the friction force is given by:

$W_f=F_f*d*cos(\theta)\\W_f=\µ*m*g*d*cos(180)\\W_f=0.08*220kg*9.8m/s^2*7.3m*(-1)\\W_f=-1259J$

so:

$W_d=\frac{1}{2}*220kg*(3.3m/s)^2+1259J\\W_d=2457J$

The power is given by:

$P=\frac{W}{t}\\\\P=\frac{2457J}{4.4s}\\\\P=558W$

and the force exerted by the dogs:

$W_d=F_d*d*cos(\theta)\\F_d=\frac{W_d}{d*cos(0)}\\\\F=\frac{2457J}{7.3m*(1)}\\\\F=337N$

4 0

3 years ago

What happens to the total mass of a substance undergoing a physical change?

Fudgin [204]

I think that your answer would be A. because matter never just goes away in any situation, even if it gets away from you.

4 0

3 years ago

Which one of the following is an example of a solution?

insens350 [35]

Answer:

it is maybe A but i'm not 100% sure

Explanation:

its the only one that is mixed

6 0

3 years ago

Do all planetary systems look the same as our own?

Svet_ta [14]

Answer:

Explanation:

A planetary system consists of at least one star and non stellar objects revolving around it.

Our solar system has one star around which there are 8 planets. However there are star systems with more than one star. These systems are called binary systems. The size of stars also vary. They also vary by orbital configuration i.e, the planets have higher eccentricity than our solar system's. The planetary systems are also classified on the basis of the number of planets in them.

So, all planetary systems do not look the same as our own.

4 0

3 years ago