Answer:
1) 5.52 cm , C) 5.5 cm
Explanation:
When a measurement is carried out, in addition to the value of the magnitude, the error or uncertainty of the measurement must occur, in a direct measurement with an instrument the uncertainty is equal to the appreciation of the instrument.
Uniform see the errors by the number of significant figures days, in this cases they are two decimals for which the appreciation of the instrument ± - 0.01
now we can analyze the measurements made
1) 5.52 cm. Validate. It is a valid measurement is within the uncertainty range
2) 6.63 cm. It does not validate. It is out of the error range
3) 5.5 cm Valid. It is within the given error range,
4) 5.93 cm Not Valid. It is out of the error range.
Answer:
D. 0.1
Explanation:
Using transformer equation,
N2/N1 = I1/I2................... Equation 1
Where N2 = secondary coil, N1 = primary coil, I1 = input current, I2 = output current.
make I2 the subject of the equation
I2 = I1/(N2/N1)............ Equation 2
From equation 2 above, For the output current of the secondary coil to be 10 times the input current, N2/N1 = 0.1
Hence the right option is D. 0.1
Answer:
i=1250000000Nm
ii=50000m/s
Explanation:
energy=force ×distance
500000N×(2.5×1000)m
=1250000000Nm
ii. Force=mass ×acceleration
500000N =40000kg ×a
500000 ÷40000=12.5a
s=1/2at^2
2500m=1/2×12.5×t^2
2500m=6.25×t^s
2500÷6.25=400
t^2=400
√t^2=√400
t=20seconds
speed=distance ×time taken
=2500m × 20s
=50000m/s
Answer:
Explanation:
The computation of acceleration of the particle down the slope is shown below:-
data provided in the question
Particle of mass = 1.3 kg i,e sliding down
Inclined = 30 to the horizontal
based on the above information
Force is given by
............ 1
and sliding force is given by
= 
Hence, the acceleration of the particle down the slope is 4.9 m/sec^2
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