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musickatia [10]
3 years ago
9

A fancart of mass 0.8 kg initially has a velocity of < 0.8, 0, 0 > m/s. Then the fan is turned on, and the air exerts a co

nstant force of < −0.3, 0, 0 > N on the cart for 1.5 seconds. What is the change in momentum of the fancart over this 1.5 second interval?
Physics
1 answer:
Anna71 [15]3 years ago
6 0

To solve this problem we will apply the concepts related to the change of the momentum. At the same time we will use Newton's second law to obtain the acceleration of the object and the kinematic equations of linear motion.

Newton's second law is defined as,

F = ma \rightarrow a = \frac{F}{m}

Here,

F = Force

m = Mass

a = Acceleration

Our values are given as,

v_i = 0.8 m/s

v_f = ?

t = 1.5s

F = -0.3N

According to this values we have that the acceleration is,

a = \frac{F}{m}

a = \frac{-0.3}{0.8}

a = -0.375m/s^2

Now applying the concepts of kinematic equations we have that the final velocity is,

v_f = v_i + at

v_f = 0.8m/s + (-0.375m/s^2)(1.5s)

v_f = 0.3375m/s

By definition we know that momentum is the product between mass and velocity, so the change in momentum would be given by

\Delta p = p_f - p_i

\Delta p = mv_f-mv_i

\Delta p = m(v_f-v_i)

\Delta p = (0.8)(0.3375-0.9)

\Delta p = - 0.45kg \cdot m/s

Therefore the change in momentum of the fancart is -0.45kg m/s

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. A ball is thrown downward at a speed of 20 m/s. Choosing
a_sh-v [17]

The final velocity is v = 20 - gt

The distance traveled by the ball at time t is y = y_o + (-20)t - \frac{1}{2} gt^2

The maximum distance traveled by the object is 0 = (20)^2 - 2g(y-y_0)

The given parameters;

initial velocity of the ball, u = 20 m/s

acceleration due to gravity, g = 9.8 m/s²

The final velocity can be calculate as;

v = 20 - gt

The distance traveled by the ball at time t;

y = y_o + (-20)t - \frac{1}{2} gt^2

The maximum distance traveled by the object is calculated as;

v^2 = u^2 - 2g(y - y_0)\\\\0 = (20)^2 - 2g(y-y_0)

Learn more here: brainly.com/question/16878713

3 0
2 years ago
A woman of mass 50 kg is swimming with a velocity of 1.6 m/s. If she stops stroking and glides to a stop in the water, what is t
Snezhnost [94]

Answer:

Impulse of force = -80 Ns

Explanation:

<u>Given the following data;</u>

Mass = 50kg

Initial velocity = 1.6m/s

Since she glides to a stop, her final velocity equals to zero (0).

Now, we would find the change in velocity.

Change \; in \; velocity = final \; velocity - initial \; velocity

Substituting into the equation above;

Change in velocity = 0 - 1.6 = 1.6m/s

Impulse \; of \; force = mass * change \; in \; velocity

Substituting into the equation, we have;

Impulse \; of \; force = 50 * -1.6

<em>Impulse of force = -80 Ns</em>

<em>Therefore, the impulse of the force that stops her is -80 Newton-seconds and it has a negative value because it is working in an opposite direction, thus, bringing her to a stop. </em>

5 0
2 years ago
Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of
natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

r'=4.12\ m

We need to calculate the path difference

Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

\lambda=1.143\ m

We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

7 0
3 years ago
Mila both 2 kg of cheese in the market to be used for her Mac and cheese recipe. How many pounds does a 2.00 kg of cheese weigh?
gogolik [260]

Answer:

The answer is 4 pounds

Explanation:

The explanation is that 1 kilogram is equal to 2 pounds so multiply the kilogram with the 1 pound

8 0
2 years ago
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prisoha [69]

Answer:

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Explanation:

3 0
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