Answer:
Explanation:
Let T be the tension in the cord.
Impulse by cord = change in momentum of block A .
T x 5s = 10 ( 2 -0) = 20
T = 4 poundal .
acceleration of block B = 2 / 5 = 0.4 m /s²
Net force applied on A = m ( g + a ) where m is mass of block B , a is acceleration of block B .
= 8 ( 32 + .4 ) = 259.2 poundal
Frictional force on block A = 259.2 - 4 = 255.2 poundal
μ x 10 x 32 = 255.2
320μ = 255.2
μ =0 .8 .
Answer:
lift
weight
thrust
air resistance
Explanation:
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Answer:
Based on the properties electrically charged particles, we have that unlike charges attract and like charges repel each other. In order for proper application of an electrostatically negatively charged paint to be properly applied on the metal body surface of a vehicle, require that for attraction, the surface of the vehicle should be grounded and positively charged so as to effectively attract the negatively charged paint particles as it exits the nozzle, to form a strong attachment with the positively charged surface of the vehicle
Explanation:
Answer:
P V = N R T ideal gas equation
P2 / P1 = T2 / T1 where the other variables are constant
P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi