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3 years ago

What is 7 more than five times the number 9 divided by 15??

1 answer:

katrin2010 [14]3 years ago

8 0

the answer is 10. 5 times 9 = 45 and it says 45 divided by 15 which is 3 and it says seven more than 9 divided by 15 so 10 bb :)

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Andrea's living room floor is a rectangle 12 feet by 15 feet. She wants to buy a rug that is geometrically similar to her living

Sliva [168]

Answer:

180 square feet

Step-by-step explanation:

A rug that is geometrically similar to her room floor is one that has the same size as her room floor.

The floor has dimensions 12 feet by 15 feet.

The area of the floor and hence, the rug is:

A = 12 * 15 = 180 square feet

She should buy a rug that is 180 square feet

7 0

4 years ago

Can someone please help me asap

Hatshy [7]

Answer:

I cant see it....

Step-by-step explanation:

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3 years ago

A, b and c are the sides of a right triangle, where side a is across from angle a, side b is across from angle b, and side c is

Vera_Pavlovna [14]

<span>Find missing length :
</span>
a² + b² = c²
c² = 19² + 34²
c² = 1517
c = √1517
c = 38.95 units.

Find missing angle A:

$\dfrac{a}{\sin(a)} = \dfrac{c}{\sin(c)}$

$\dfrac{19}{\sin(a)} = \dfrac{38.95}{\sin(90)}$

$\sin(a) = 0.488$

$a = sin^{-1} (0.488)$

$a = 29.2 \textdegree$

Find Missing B:

$\dfrac{b}{\sin(b)} = \dfrac{c}{\sin(c)}$

$\dfrac{34}{\sin(b)} = \dfrac{38.95}{\sin(90)}$

$\sin(b) = 0.873$

$b = sin^{-1}(0.873)$

$b = 60.8 \textdegree$

Answer: Missing length = 38.95 units ; Missing angles = 29.2° and 60.8°

8 0

4 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$