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2 years ago

6

The results of a recent survey of the students at Rockdale Middle School show that 17 out of every 22 students enjoy the cafeter

ia’s cheeseburgers, 56 of the students enjoy the cafeteria’s pizza, and 80.5% enjoy the cafeteria’s salad bar. Based upon this survey, which of these three foods is most enjoyed?

1 answer:

aalyn [17]2 years ago

5 0

Answer:

80.5%

Step-by-step explanation:

Because 17/22 converted to a percent is 72% and 56 is not right so 80.5% must be the right choice.

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What da answer to 5. and 6? help is needed please plzzzz

denpristay [2]

5 is 130.48
6 is 826.66

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2 years ago

Determine the image of the point (-5, 2) under a rotation of 90° about the origin.

8_murik_8 [283]

Answer:

(2, 5)

Step-by-step explanation:

Rotation clockwise 90° can be accomplished by the transformation ...

(x, y) ⇒ (y, -x)

so

(-5, 2) ⇒ (2, 5)

5 0

2 years ago

Help ASAP please

mr Goodwill [35]

Answer:

19cm

Step-by-step explanation:

x * 5x = 1805

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x^2 = 361

square root of that is 19

5 0

2 years ago

Read 2 more answers

1. Find the circumference of a circle with a radius of 23 inches. *

xeze [42]

Answer:

I think 46

Step-by-step explanation:

can't really explain I just know

6 0

2 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago